Make x the subject of the equation: y = 4(x+2)/5x-1

1st multiply out the brackets:

y = 4x + 8 / 5x - 1

Next multiply both sides by the denominator onf the RHS:

y(5x-1)  = 4x + 8

Again, multiply out the brackets:

5xy - y = 4x + 8

Rearrange the equation so that all terms with x are on the LHS:

5xy - 4x = y + 8

Factor out the x:

x(5y-4) = y + 8

Divide both sides by the brackets to make X the subject of the equation:

ANSWER

x = y + 8 / 5y - 4 

NR

Related Maths 11 Plus answers

All answers ▸

The point p lies on the curve with eqn x = (4y - sin(2y)^2, given that p has coordinates (p,π/2), p is a constant, a) find the exact value of p; the tangent to the curve at P cuts the y-axis at A, b) use calculus to find the coordinates of A.


How many 1/3's are there in 9?


How many thirds are there in 9?


fifty two thousand, seven hundred, and twenty four people went to a concert. Write this in numbers and round it to the nearest thousand.