Mom has blood type A and father has blood type B. a) If mom has AA and dad B.B. genotype, determine their children’s genotype. b) If mom has AO and father has B.B. genotyoe, determine their children’s genotype and the likelihood.

If the mom has blood type A, her genotype could either be AA or AO. She has at least one copy of A allele. 

If the father has blood type B, his genotype could either be BB or BO. He has at least one copy of B allele. 

a) If mom has AA genotype and father has BB genotype, all the children will have AB genotype=> AB type of blood => 100% chance to have children with AB type of blood 

Mom: AA separates into: A, A

Father: BB separated into: B, B 

=> AA x BB => AB, AB, AB, AB (100% AB) 

If you combine mom’s each copy of allele with father’s each copy of allele, the only combination will be AB. 

b) If the mom has AO genotype and the father has BB genotype, 50% of The children will have AB genotype and 50% of the children will have BO genotype. => 50% chance to have children with AB type of blood and 50% chance to have children with B type of blood 

Mom: AO separates into: A, O 

Father: BB separates into: B, B 

=> AO x BB => AB, AB, BO, BO (50% AB, 50% B)

If you combine mom’s each copy of allele with the father’s, the results will be AB and BO.