x^2-5x-50=0. Solve for the positive value of x

recognise this equation has the form ax^2 + bx + c =0. An equation with this form is a quadratic. Recognise in a quadratic equation there will be 2 values of x that will equal 0. These 2 values will multiply to make 'ac' add add to make 'b'. In this example, 'ac' is 1x-50=-50, and b is -5. What 2 numbers multiply to make -50, and add up to make -5? -10 and +5 multiply to make -50, and add to make -5. Therefore you would re-write the initial equation as (x-10)=0 and (x+5)=0. These become 2 new equations, now solve for these.x=10 and x=-5. The positive value of x is 10.

EF
Answered by Ellis F. Maths tutor

2696 Views

See similar Maths 13 Plus tutors

Related Maths 13 Plus answers

All answers ▸

Expand the brackets to create an equation. (2x+7)(x-3)


why is (x+y)^2 ≠ x^2 + y^2


Factorise the following a) 8x + 6y b) 7xy + 3xzy c)5xyz - 20x^2y^2z


find the value of 2^3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences