Using the product rule, differentiate y=(2x)(e^3x)

The product rule states that if y=uv, where u and v are both functions of x, then dy/dx = u(dv/dx) + v(du/dx)Therefore, the differential of 2xe3x can be found by letting 2x=u and e3x =v.u=2x,du/dx = 2
v=e3xdv/dx = 3e3x
dy/dx = u(dv/dx) + v(du/dx)dy/dx = 2x(3e3x) + e3x(2)dy/dx = 6xe3x + 2e3xdy/dx = 2e3x(3x+1)

Answered by Christy O. Maths tutor

4546 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

When I integrate by parts how do I know which part of the equation is u and v'?


find dy/dx of the equation y=ln(x)2x^2


Integrate cos^2x + cosx + sin^2x + 3 with respect to x


For sketching the graph of the modulus of f(x) (in graph transformations), why do we reflect in the x-axis anything that is below it?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy