Solve the equation 2log (base 3)(x) - log (base 3)(x+4) = 2

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First express as a single logarithm as follows. The number in front of the logarithm remembering log rules can be rewritten as the power of the number in the bracketsSo rewriting the RHSlog3(x2) - log3(x+4)log3(x2/(x+4))remember inverse log3 is to the power of 3so2 = log3(x2/(x+4))32=(x2/(x+4))expanding and solving x2-9x-36=0(x-12)(x+3)=0x=12 as cannot do a negative logarithm of a number

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