First express as a single logarithm as follows. The number in front of the logarithm remembering log rules can be rewritten as the power of the number in the bracketsSo rewriting the RHSlog_{3}(x^{2}) - log_{3}(x+4)log_{3}(x^{2}/(x+4))remember inverse log_{3} is to the power of 3so2 = log_{3}(x^{2}/(x+4))3^{2}=(x^{2}/(x+4))expanding and solving x^{2}-9x-36=0(x-12)(x+3)=0x=12 as cannot do a negative logarithm of a number

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