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Ka for ethanoic acid = 1.74 x 10-5 mol dm-3 . In what proportions would you have to mix solutions of ethanoic acid and sodium ethanoate of the same concentration in order to produce a buffer solution of pH 5.00?

First we write the equation for Ka: Ka = [H+] [A-] / [HA]We then use the given pH of 5 to calculation the H+ concentration in the solution: 10-5 = 0.00001 mol/dm3We then rearrange the Ka expression, to find [A-] / [HA], which is the same as the proportions of salt to acid.The full calculation is completed on the whiteboard.The final answer is 1.74.

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