873 views

### Solve the simultaneous equations 5x+2y=11 and x-y=-2.

Simultaneous Equations are equations involving 2 or more unknowns that are to have the same value in each equation. The aim is to eliminate all except one unknown which will then allow us to find the value of that unknown. From this any other unknowns can be found. There are 2 main methods we can use to solve these problems:

1.Solving by Elimination

This method works due to 2 properties of equations:

1.Multiplying or dividing the expression on each side by the same number does not alter the equation.

2.Addition of 2 equations produces another valid equation.

We must manipulate the 2 equations so that when added or subtracted an unknown is removed. First we must label our equations:

(1)5x+2y=11

(2)x-y=-2

Now we must manipulate one or both of the equations so we can remove an unknown by elimination.

For example here the easiest method would be to multiply equation (2) by 2 to obtain equation (3)2x-2y=-4. Then by adding equation (1) to equation (3) we would eliminate y from our equations.

This would give us 7x=7. Therefore we can see that x=1.

Now we substitute this value of x back into either of our original equations (1) or (2). If we substitute back into (2) we obtain the equation 1-y=-2. From this we can see that y=3.

Therefore we have solved the simultaneous equations and obtained the answer of x=1 and y=3.

2.Solving by Substitution

This involves making one of the variables the subject of the equation then substituting this equation into the other simultaneous equation hence removing one of the unknowns.

For this equation if we make x the subject in equation (2) we obtain x=y-2. Then by substituting this x expression into equation (1) we obtain 5(y-2)+2y=11.

By expanding the bracket and collecting like terms we obtain the equation 7y=21. We can see from this that y=3.

Then similarly to before we substitute this y value back into either equation (1) or (2).

If we substitute back into equation (2) we obtain the equation x-3=-2.

We can see from this that x=1.

Therefore we have obtained the answer of x=1, y=3 which is the same as for solving by elimination.

For simple simultaneous equation problems such as this one, elimination is often the more efficient method. However as problems become more complex substitution is often required as integers may not always be used.

1 year ago

Answered by Peter, a GCSE Maths tutor with MyTutor

## Still stuck? Get one-to-one help from a personally interviewed subject specialist

#### 780 SUBJECT SPECIALISTS

£18 /hr

Degree: Mathematics (Masters) - Bath University

Subjects offered:Maths, Further Mathematics

Maths
Further Mathematics

“Hi! I am studying Mathematics at Bath University and I am passionate about teaching, and learning mathematics.”

MyTutor guarantee

|  1 completed tutorial

£36 /hr

Degree: Computer Science (Doctorate) - Manchester University

Subjects offered:Maths, Italian+ 3 more

Maths
Italian
ICT
Computing
-Personal Statements-

“PhD Student in Computer Science with a passion for interdisciplinary research and teaching”

£20 /hr

Degree: Medicine A100 (Bachelors) - Liverpool University

Subjects offered:Maths, Science+ 6 more

Maths
Science
Physics
Chemistry
Biology
.UKCAT.
-Personal Statements-
-Medical School Preparation-

“Hi, I'm Chai and I'm a fifth year medical student that is passionate about helping students achieve the best of their potential!”

Currently unavailable: for regular students

Degree: Engineering Science (Masters) - Oxford, Balliol College University

Subjects offered:Maths, Physics+ 5 more

Maths
Physics
Further Mathematics
Electronics
Biology
.PAT.
-Personal Statements-

“I am a second year Engineering Science student at Balliol College, Oxford University. One of the most appealing features of studying engineering is being able to apply Mathematics and Physics theory to real world problems. I feel that...”

### You may also like...

#### Other GCSE Maths questions

differentiate x^3(1+x)^5 with respect for x

Simplify (3x^2 - 15x)/(3x^2 - 13x -10)

Solve these simultaneous equations, (1) [5a - 3b = 16], (2) [2b - 3a = -9] ?

Rearrange the equation y=3x+2 to make x the subject.

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this.