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### How does one find the derivative of ln(x)?

Let

y = ln(x)

Then

x = e^y

[ ln(x) = ln(e^y) = y ln(e) = y*1 = y ]

Taking the derivative of this we get

dx/dy = e^y

Taking the reciprocal we get

dy/dx = 1/e^y = 1/x

So the derivative of ln(x) is

d(ln(x))/dx = 1/x

1 year ago

Answered by Anya, an A Level Maths tutor with MyTutor

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