Find the integral of 3x^2 + 4x + 9 with respect to x.

We must first remember that to integrate, we must increase the power by 1 and divide by this new power.

Therefore, to integrate 3x^2 + 4x + 9, we take the first term, 3x^2. Using the above method, we find that the integral of this is (3x^3)/3 = x^3.

Taking the second term, 4x, we find the integral to be (4x^2)/2 = 2x^3.

Taking the final term, 9, we find the integral to be (9x)/1 = 9x.

As the question gives an indefinite integral (an integral without any limits) we must also remember to add a constant, which we can call C.

Therefore, the integral of 3x^2 + 4x + 9 with respect to x is 2x^2 + x^3 + 9x + C.

Answered by Dylan J. Maths tutor

7072 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find dy/dx in terms of t of the parametric equations x=4e^-2t, y=4 - 2e^2t


The points A and B have coordinates (1, 6) and (7,− 2) respectively. (a) Find the length of AB.


Integrate the function : F'(x)=3x^2+4x-5


Find the gradient of a straight line with the points P(5,3) and Q(8,12)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy