I cannot praise this tutor enough. Highly skilled in mathematics, teaches at the student's pace, patient and super efficient. A conscientious person who responds immediately to messages. The lesson was tailor made to suit my own needs. Mayur is excellent at pin pointing math problems quickly - taking things back to basic principals where needed. A most enjoyable tutorial - I would highly recommend this very gifted tutor to students of every ability.

Elizabeth, Student

My son says he's very lucky to have Joseph's help. He's an excellent tutor, 100% reliable, very generous with his time and patient and willing to direct help exactly where it's needed. My son's made progress after only a few lessons and is motivated to work much harder on a subject he finds hard. Couldn't recommend him more highly. Thank you Joseph.

Alison, Parent from Hertfordshire

Why limit yourself to someone who lives nearby, when you can choose from tutors across the UK?

By removing time spent travelling, you make tuition more convenient, flexible and affordable

We've combined live video with a shared whiteboard, so you can work through problems together

All your tutorials are recorded. Make the most out of your live session, then play it back after

Usually we cover both subject knowledge and exam technique, although that can change depending on each individual student. Then we go through diagrams, and they ask questions, and we go from there.

Lots of students say that the classes are too big in school, or that they don't have time to ask teachers after lessons. In my tutorials, we take time to explore things in a little in a bit more detail.

I always look up the board my students are taking so the lessons are really relevant. Then we go through past papers or set texts, whatever the student finds helpful.

I use the shared whiteboard. We make diagrams together and label them, and often the student prints it off because they know it's right and they completely understand it.

After tutoring one girl went and told all her friends the new explanation I gave her. And she was so excited about what she wrote in the exam she emailed me immediately afterwards.

There was one girl who had her exam on Monday. She wanted tuition on Friday, Saturday and Sunday beforehand. It was very intense, but she said the exam went well.

All angles in a triangle add up to 180 degrees. In a right angled triangle, we know one angle is 90 degrees. In the question, it is given that another angle is 63 degrees. So the remaining angle must be 180 - (90 +63) = 27 degrees

Answered by Rebekah L.

Studies Medicine at Kings, London

I will run through an example of how to solve a set of simultaneous equations. In simultaneous equations you are given two or more algebraic equations and you need to solve them for the variables, usually called x and y. You start off by trying to get equivalent coefficients for either the x or y value in both of the equations. For example: (1) 4x + y = 24 and (2) 7x + 3y = 47. Here we can multiply equation (1) by 3 so that both the x coefficients are equal to 3. So 3*(1) is equivalent to 12x + 3y =72. Now we can subtract (2) from 3*(1). This gives 5x + 0y = 25, giving 5x = 25 therefore x = 5. Substituting x back into equation (1) we get 4*5 + y =24. So y = 24 - 20 and y = 4. Giving us the solutions: x=5 and y=4.

When dividing fractions you must remember the KEEP, CHANGE, FLIP rule.
KEEP - The first fraction you KEEP as it is, you don't change it.
CHANGE - You now change the sign from a division to a multiplication.
FLIP - You FLIP the last fraction over so the denominator is now the numerator and vice versa.
You now have a simple multiplication question which you should be familiar with. If not then you simply multiply the two numerators to get the answer numerator, and multiply the two denominators to get the answer denominator.

Suppose we have two vectors __U__(a1,b1) and __V__(a2,b2). Hence, the distance between __U__ and __V__ will be given by the formula: d=sqrt((a1-b1)^{2 }+ (a2-b2)^{2})

This is a case of substitution. 2(3)+(7) =13

Median: Reorder the data in numerical order, then select the value that lies directly in the middle of the data line - if there is an odd number of data, the median value is the middle number and if there is an even number of data, the median is the mean of the two middle points.
i.e. 2, 6, 7, 8, 9, 11, 17, 18, 21. The median is 9.
Mean: Find the total sum of the data and then divide this sum by the number of data points there are.
i.e. 11+9+21+6+18+2+17+8+7 = 99
99 / 9 = 11. The mean is 11.
Therefore, the difference between the median and the mean is 11-9 = 2.

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With such a variety of questions, GCSE Maths can be a real headache for students. In individual sessions with a GCSE Maths tutor you can focus on exactly the topics you need help with. In our online classroom, tutors use diagrams, graphs and illustrations to enhance their lessons.

From algebra to indices,

they will explain concepts at your own pace and in new ways so that you fully understand them.So when your GCSE exams come round, you'll be able to tackle even the most difficult questions on the paper.