<p>With such a variety of questions, GCSE Maths can be a real headache for students. In individual sessions with a GCSE Maths tutor you can focus on exactly the topics you need help with. In our online classroom, tutors use diagrams, graphs and illustrations to enhance their lessons.</p>
<p>From algebra to indices, <strong>they will explain concepts at your own pace and in new ways so that you fully understand them.</strong> So when your GCSE exams come round, you'll be able to tackle even the most difficult questions on the paper.</p>

- Recent experience
- Proven exam success
- Strong communication skills
- Personally interviewed
- A or A* in their subjects
- Up-to-date syllabus knowledge

I cannot praise this tutor enough. Highly skilled in mathematics, teaches at the student's pace, patient and super efficient. A conscientious person who responds immediately to messages. The lesson was tailor made to suit my own needs. Mayur is excellent at pin pointing math problems quickly - taking things back to basic principals where needed. A most enjoyable tutorial - I would highly recommend this very gifted tutor to students of every ability.

Elizabeth, Student

Jack has been tutoring my 12 year old son for about 2 months now and is really beginning to improve his confidence and mathematical ability. The lessons are fun and very thorough, often reinforcing a topic covered in classwork or tricky homework, leaving him confident and ready to move on to the next one. Unlike in school, during sessions with Jack my son is never afraid to say when he doesn't fully understand something, ensuring 100% confidence in a topic. Jack has been very flexible with the timings of our sessions and has endless patience. This is a great way to sign up to a tutor and if you are lucky enough to have Jack you will not be disappointed.

Julia, Parent from Hampshire

Callum has become so much more confident with his maths since taking you on as his maths tutor. He not only enjoys your tutorials he says he has gained a lot from them since starting your tutalage. Thank you so much for your time, effort and flexibility over the last several months. Regards Stephen Brown (Callums dad)

Callum, Student

Why limit yourself to someone who lives nearby, when you can choose from tutors across the UK?

By removing time spent travelling, you make tuition more convenient, flexible and affordable

We've combined live video with a shared whiteboard, so you can work through problems together

All your Online Lessons are recorded. Make the most out of your live session, then play it back after

Usually we cover both subject knowledge and exam technique, although that can change depending on each individual student. Then we go through diagrams, and they ask questions, and we go from there.

Lots of students say that the classes are too big in school, or that they don't have time to ask teachers after Online Lessons. In my Online Lessons, we take time to explore things in a little in a bit more detail.

I always look up the board my students are taking so the Online Lessons are really relevant. Then we go through past papers or set texts, whatever the student finds helpful.

I use the shared whiteboard. We make diagrams together and label them, and often the student prints it off because they know it's right and they completely understand it.

After tutoring one girl went and told all her friends the new explanation I gave her. And she was so excited about what she wrote in the exam she emailed me immediately afterwards.

There was one girl who had her exam on Monday. She wanted tuition on Friday, Saturday and Sunday beforehand. It was very intense, but she said the exam went well.

First of all we need to get all of the x's on one side and all the numbers on the other side. Therefore to do this firstly we should add 2 to both sides.
8x > 4x +8
Secondly we need to -4x from both sides
4x > 8
Finally we want to get a single value for x so we need to divide each side by 4
x > 2

Answered by Rory D.

Studies BSc Economics and Finance at Bristol

(x+2)(x-3)(x+4)^2 = (x^2 - x - 6)(x^2 + 8x + 16) = (x^4 + 8x^3 +16x^2 - x^3 - 8x^2 -16x - 6x^2 - 48x - 96)
= x^4 +7x^3 + 2x^2 - 64x - 96)

Answered by Roisin G.

Studies P at Queen's, Belfast

This question demonstrates how the exponential function can be used to simplify equations when differentiating. In its current form the equation appears complex and the method is not at all clear. However, if we take the ln of both sides, we can simplfy this equation enormously. Using the laws of logs we end up with the equation: ln(y)=sin(x)ln(2). This can be differentiated easily via implicit differentiation to give: (1/y)(dy/dx)=cos(x)ln(2). Multiplying by y gives: dy/dx=ycos(x)ln(2). The final step in this method is substituting our initial equation into this to give dy/dx=2sin(x)cos(x)ln(2).
The reason this problem appears difficult is because taking ln of both sides is not an first obvious step. Furthermore, this method involves substituting an equation back into its derivitive. Often this can throw people off as they do not initially calculate dy/dx in terms of x. This is a problem which I personally had intial difficulty with. The telltale sign of a problem like this is having a variable in a power.

x_{1 }= (-b + (b^{2 }- 4ac)^{1/2})/2a and x_{2 }= (-b - (b^{2 }- 4ac)^{1/2})/2a. So with the values a = 1, b = 3 and c = 2: x_{1 }= (-3 + (3^{2 }- 8)^{1/2})/2 and x_{2 }= (-3 - (3^{2 }- 8)^{1/2})/2, x_{1 }= (-3 + 1)/2 = -1 and x_{2 }= (-3 - 1)/2 = -2.

Answered by Rebecca D.

Studies MMATH Mathematics Degree at Leeds

x^{2}+2x+1=0, (x+1)(x+1)=0, (x+1)^{2}=0. So x=-1

Answered by Rebecca D.

Studies MMATH Mathematics Degree at Leeds

x^{2}+5x+6=0
(x+3)(x+2)=0
x=-3 and x=-2

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