Nicholas B. GCSE Maths tutor, A Level Maths tutor

Nicholas B.

£18 - £20 /hr

Currently unavailable: for new students

Studying: Mathematics with Study in Continental Europe (Masters) - Bristol University

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About me

Hi, I'm Nick. Maths is one of my great passions, and I'm thoroughly the first year of my four year degree course studying Mathematics at the University of Bristol. I'll spend my third year studying maths in Bordeaux, France. I'm just starting with MyTutorWeb, but I often help out other students with their work.

I am eager to help out with A level and GCSE Maths, and my session times are very flexible. I'm here to help you learn and enjoy mathematics!

If you'd like to talk to me about anything, you can send me a meet the tutor request and we'll soon arrange a session.

Hi, I'm Nick. Maths is one of my great passions, and I'm thoroughly the first year of my four year degree course studying Mathematics at the University of Bristol. I'll spend my third year studying maths in Bordeaux, France. I'm just starting with MyTutorWeb, but I often help out other students with their work.

I am eager to help out with A level and GCSE Maths, and my session times are very flexible. I'm here to help you learn and enjoy mathematics!

If you'd like to talk to me about anything, you can send me a meet the tutor request and we'll soon arrange a session.

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A
Further MathematicsA-level (A2)A*
FrenchA-level (A2)B
MusicA-level (A2)B

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr

Questions Nicholas has answered

What are the roots of 3x^2 + 13x + 4 ?

To find the roots, we solve the equation 3x2 + 13x + 4 = 0.

We could try factorising the equation, which gives us

(3x + 1)(x + 4) = 0

So the roots are x = -1/3 and x = -4.

Alternatively, we could use the quadratic formula;

x = (-b +/- sqrt( b2 - 4ac)) / 2a

[note that sqrt(x) is the square root of x]

So here;

x= (-13 +/- sqrt(132 - 4*3*4)) / 2*3

   = (-13 +/- sqrt(169 - 48)) / 6

   = (-13 +/- sqrt(121)) / 6

   = (-13 +/- 11) / 6

   = (-13 + 11) / 6     or     (-13 - 11) / 6

   = -2 / 6      or      -24 / 6

   = -1 / 3      or      -4

So again, the roots are x = -1 / 3 or x = -4.

To find the roots, we solve the equation 3x2 + 13x + 4 = 0.

We could try factorising the equation, which gives us

(3x + 1)(x + 4) = 0

So the roots are x = -1/3 and x = -4.

Alternatively, we could use the quadratic formula;

x = (-b +/- sqrt( b2 - 4ac)) / 2a

[note that sqrt(x) is the square root of x]

So here;

x= (-13 +/- sqrt(132 - 4*3*4)) / 2*3

   = (-13 +/- sqrt(169 - 48)) / 6

   = (-13 +/- sqrt(121)) / 6

   = (-13 +/- 11) / 6

   = (-13 + 11) / 6     or     (-13 - 11) / 6

   = -2 / 6      or      -24 / 6

   = -1 / 3      or      -4

So again, the roots are x = -1 / 3 or x = -4.

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3 years ago

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