Jack W. A Level Chemistry tutor, A Level Biology tutor, GCSE Maths tu...

Jack W.

Currently unavailable: for new students

Degree: Medicine (Bachelors) - Newcastle University

Contact Jack
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Jack

About me

Hi there!

My name is Jack, I currently study Medicine and Newcastle University and have a real passion for tutoring. I took a gap year working in a secondary school teaching GCSE Maths. During this time I took many sessions on improving my teaching styles and sharing my abilities with my colleagues. 

I am looking to tutor Chemisty and Biology to A level and GCSE standard and Maths and music to GCSE level. I achieved A grades in all four at A level and A* grades at GCSE. 

I would make an excellent tutor for you because of my high level of subject knowledge and copious experience in teaching.

I hope to hear from you soon :)

Subjects offered

SubjectLevelMy prices
Biology A Level £20 /hr
Chemistry A Level £20 /hr
Biology GCSE £18 /hr
Chemistry GCSE £18 /hr
Maths GCSE £18 /hr
Music GCSE £18 /hr

Qualifications

QualificationLevelGrade
ChemistryA-LevelA
BiologyA-LevelA
MathematicsA-LevelA
MusicA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

26/09/2014

Currently unavailable: for new students

Ratings and reviews

5from 5 customer reviews

Sylvie (Parent) February 29 2016

Anaelle is delighted with her classes and finds she is doing good progress. Many thanks.

Julia (Parent) December 1 2015

Jack has been tutoring my 12 year old son for about 2 months now and is really beginning to improve his confidence and mathematical ability. The lessons are fun and very thorough, often reinforcing a topic covered in classwork or tricky homework, leaving him confident and ready to move on to the next one. Unlike in school, during sessions with Jack my son is never afraid to say when he doesn't fully understand something, ensuring 100% confidence in a topic. Jack has been very flexible with the timings of our sessions and has endless patience. This is a great way to sign up to a tutor and if you are lucky enough to have Jack you will not be disappointed.

Ed (Student) November 2 2015

Ed is really enjoying his lessons with Jack. Very beneficial.

Julia (Parent) October 20 2015

3 sessions so far & I think Ed is really beginning to improve. Ed is enjoying his sessions with Jack and progress is being made.
See all reviews

Questions Jack has answered

Describe the process of evolution (6 Marks)

Mutations in genetic code occur naturally leading to different alleles in genes. (1 mark) This leads to variation within a species. (1 mark) Variation provides some individuals with traits which mean they are more capable of surviving in their specific environment, this is known as a  selecti...

Mutations in genetic code occur naturally leading to different alleles in genes. (1 mark)

This leads to variation within a species. (1 mark)

Variation provides some individuals with traits which mean they are more capable of surviving in their specific environment, this is known as a selective advantage. (1 mark)

Those with the selective advantage are more likely to survive and reproduce than those without it. (1 mark)

This means that more offspring will be born with the advantageous allele and will out-compete those without it. (1 mark)

Over thousands of years this process will continue and gradually alter the traits of a species in order to make them more able to survive in their environment.

see more

1 year ago

376 views

Factorise X^2 + 1X -12

Because the highest power of X is 2, this is a Quadratic Equation When factorised, these look like         (x + a)(x + b)                 where a & b are constants To factorise this, we need to find 2 numbers which add together to make the coefficient (number in front of) X and multiply to ma...

Because the highest power of X is 2, this is a Quadratic Equation

When factorised, these look like 

       (x + a)(x + b)                 where a & b are constants

To factorise this, we need to find 2 numbers which add together to make the coefficient (number in front of) X and multiply to make the number at the end.

So we need two numbers which add together to make +1 and multiply to make -12       +4 & -3

a & b in the form above are replace by these to numbers, so the answer is

(x+4)(x-3)

see more

1 year ago

314 views
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Jack

Still comparing tutors?

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

Cookies:

We use cookies to improve our service. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok