Oliver M. Uni Admissions Test .STEP. tutor, A Level Maths tutor, GCSE...

Oliver M.

Currently unavailable: for regular students

Degree: MMaths (Masters) - Warwick University

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About me

A bit about me:

Having been through A-level and STEP maths, I am very familiar with the ins and outs of how to get the most marks out of a paper. With fresh insights from degree-level maths, I am very excited to work with you through your maths course.

Past experience:

I have had plenty experience tutoring in the past. I tutored fellow students informally at A-level maths and physics during my spare time, and spent a year as a teaching assistant to a year 7 science class, for which I won a Jack Petchy award. I really enjoy maths problems, and love being able to discuss methods and share insights with others.

Note on STEP:

STEP problems are all unique, and it isn’t something that is particularly easy to teach. What I would like to offer is an intuitive problem solving approach, teaching a new way of thinking about problems which is invaluable in higher level maths.

I look forward to meeting you!

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Maths GCSE £18 /hr
.STEP. Uni Admissions Test £25 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
Further MathsA-LevelA
PhysicsA-LevelA
Step 2Uni Admissions Test2
Step 3Uni Admissions Test1
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

Questions Oliver has answered

How do you intergrate ln(x)?

There's a nice trick here you can do, treat the equation as 1*ln(x) then intergrate by parts. Differentiating ln(x) gives 1/x, while intergrating 1 gives x So your left with a much easier intergration x*ln(x)-(Intergral sign)x* 1/x dx which is simply x*ln(x)-x

There's a nice trick here you can do, treat the equation as 1*ln(x) then intergrate by parts.

Differentiating ln(x) gives 1/x, while intergrating 1 gives x

So your left with a much easier intergration

x*ln(x)-(Intergral sign)x* 1/x dx

which is simply x*ln(x)-x

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1 year ago

371 views

How do you solve a graphing problem on STEP?

Well, as with all STEP questions, each problem is unique. But with graphing problems there are some nice things you can do to help break down the problem. Firstly, ALWAYS DIFFERENTIATE, i cannot stress this enough. If you know how your gradient is changing, this gives a lot about what a graph ...

Well, as with all STEP questions, each problem is unique. But with graphing problems there are some nice things you can do to help break down the problem. Firstly, ALWAYS DIFFERENTIATE, i cannot stress this enough. If you know how your gradient is changing, this gives a lot about what a graph looks like. Secondly, look for roots to both you equation and its derivative. This is a BIG part of these questions and where the most marks will be awarded. Find where your graph hits the y and x axis, and find where the fixed points are. Finally, once you have all your fixed points, make sure to note if they are a maximum, minimum or a turning point.

Now, you should have a pretty good idea of how your graph looks, but there's still one more thing we can do. Find what your graph looks like as it tends to +/- infinity

For example as y = e^x - x^3 tends to infinity, e^x will increase much faster than x^3, so will look a lot like e^x for large x

But for large negative x, e^x is essentially 0, so the graph will look pretty much like x^3

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1 year ago

252 views
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