__My background__

I study postgraduate Computer Science at University College London, and before that I graduated from the University of Edinburgh reading Philosophy & Economics.

**I truly believe everybody has the potential to excel in mathematical disciplines**, since we all speak and understand language. We combine symbols into new sentences according to grammar, we perform logical deductions, and we seek to invoke pictures in each others' minds. This is precisely what mathematics is about too.

I have volunteered as a teaching assistant in a GCSE maths class, and I have tutored various students for __GCSE__ and __A-level maths__, __physics__ and __economics.__

__My approach to teaching__

But I understand mathematical subjects can be daunting, to say the least! So I am all too happy to explain a concept from __several angles__, until it clicks with the student and they are able to describe it in their own words.

I think it's often good to __begin with a casual discussion__ of the topic in question, to get a sense of *why *it's important, placing it in the wider body of human knowledge. Then it comes alive, beyond just being an examinable topic, making it much easier to __work through concrete problems__.

We can work from a particular exam syllabus, textbook, or simply a chosen topic.

I really get a kick out of maths/science and I enjoy sharing that with others. Most importantly, __I want sessions to be fun__ because this makes it so much easier to learn effectively.

__Next steps__

Please feel free to get in touch with any queries. You can reach me via the MTW webmail system or arrange a free "Meet The Tutor" session to find out if I'm the right tutor for you!

__My background__

I study postgraduate Computer Science at University College London, and before that I graduated from the University of Edinburgh reading Philosophy & Economics.

**I truly believe everybody has the potential to excel in mathematical disciplines**, since we all speak and understand language. We combine symbols into new sentences according to grammar, we perform logical deductions, and we seek to invoke pictures in each others' minds. This is precisely what mathematics is about too.

I have volunteered as a teaching assistant in a GCSE maths class, and I have tutored various students for __GCSE__ and __A-level maths__, __physics__ and __economics.__

__My approach to teaching__

But I understand mathematical subjects can be daunting, to say the least! So I am all too happy to explain a concept from __several angles__, until it clicks with the student and they are able to describe it in their own words.

I think it's often good to __begin with a casual discussion__ of the topic in question, to get a sense of *why *it's important, placing it in the wider body of human knowledge. Then it comes alive, beyond just being an examinable topic, making it much easier to __work through concrete problems__.

We can work from a particular exam syllabus, textbook, or simply a chosen topic.

I really get a kick out of maths/science and I enjoy sharing that with others. Most importantly, __I want sessions to be fun__ because this makes it so much easier to learn effectively.

__Next steps__

Please feel free to get in touch with any queries. You can reach me via the MTW webmail system or arrange a free "Meet The Tutor" session to find out if I'm the right tutor for you!

No DBS Check

Let's begin by reviewing a fairly simple (linear) equation:

**(1)** *y = 2x + 3*

**(1) **describes the relationship between two variables, *x* and *y*. Given a value for one, we can use **(1)** to work out the value of the unknown. For instance, when *x=4*, *y=11*.

Differential equations are more general. They include __derivative terms__, denoted *dy/dx* or *y'*. Let us consider an example:

**(2)** *y' = dy/dx = ky*

While **(1)** described the relation between two variables, **(2)** describes the relation between *y*'s slope (with respect to *x*) and *y* itself. In English, it says that "*y*'s slope is directly proportional to *y*." Unlike **(1)**, the solution to **(2)** is a __function__ y, that satisfies the above description. But what kind of function has these properties? Let us solve **(2)** to find out:

* Take all the '*x*' terms to one side, and all the ‘*y’* terms to the other side:

*dy/dx = ky*

*dy = ky dx*

*dy/y = k dx*

*(1/y) dy = k dx*

* Take the integral of both sides (we omit some details about definite integrals and boundary conditions, for simplicity):

*INTEGRAL**( (1/y) dy) = **INTEGRAL**(k dx)*

* Evaluate the above integral:

*ln(y) = kx*

* Which is true if and only if:

*e*^{kx}* = y*

Thus we have shown that the exponential function *y(x) = e*^{kx} satisfies the differential equation **(2)**. This is what we should expect, since (2) said "*y*'s slope is directly proportional to *y*" and this is exactly how the number e is defined.

In further study, you will find that differential equations like **(2)** have applications in diverse fields such as: in Economics, to model growth rates and continuously compounded interest; Physics, to model radioactive decay or damped oscillations; in Biology to model bacteria populations. Now let us consider a more difficult example:

**(3)** ∂^{2}ψ/∂x^{2} = (1/v^{2})(∂^{2}ψ/∂t^{2})

**(3)** looks a little daunting but it is not much more complicated than **(2)**. The solution to **(3)** needs to be a function *ψ(x, t)*. *x* stands for a spatial direction, and *t* is time. *v* stands for ‘speed.’ We are given details about how *ψ*’s second (partial) derivatives, with respect to *x* and *t*, relate to each other. **(3)** is known to Physicists as the 'Wave Equation', because it can be derived by carefully studying springs in oscillation and sine/cosine waves like **(4)** are solutions to it.

**(4) ***ψ = Asin(kx - **ω**t**)*

Let us verify this.

* Calculate **(4)**’s second partial derivative with respect to *x* (we will need the Chain Rule):

**(5)** ∂^{2}ψ/∂x^{2}*= -k ^{2}*

* Calculate **(4)**’s second partial derivative with respect to *t*:

**(6)** ∂^{2}ψ/∂t^{2}*= -ω*^{2}*Asin(kx - **ω**t**)*

* We also need the following result (known as a dispersion relation). In physics, It can be shown that:

**(7)** *ω = kv*

where *ω* is ‘angular frequency’, *k* is ‘wavenumber’ and *v* is the speed that a wave propagates at.

* Substituting **(5)** and **(6)** into **(3) **gives:

*-k*^{2}*Asin(kx - **ω**t**) = -**(1/v*^{2}*)**ω*^{2}*Asin(kx - **ω**t**)*

*-k*^{2}* = -(1/v*^{2}*)**ω*^{2}

*k*^{2}*/**ω*^{2}* = 1/v*^{2}

*v*^{2}* = **ω*^{2}*/k*^{2}

*kv = **ω*

* Which we know to be correct because of result **(7)**, which follows from the definitions of ‘angular frequency’, ‘wavenumber’ and ‘wave speed’.

Hence the function *ψ(x, t) = Asin(kx - **ω**t**)* is a solution to the differential equation **(3)**. In fact, Schrödinger’s equation is a famous wave equation, incorporating complex numbers, whose solution is the ‘wavefunction’ of a system of particles. So I hope you can see, from this brief introduction, that we can get a lot of mileage out of this concept of ‘differential equations’!

Let's begin by reviewing a fairly simple (linear) equation:

**(1)** *y = 2x + 3*

**(1) **describes the relationship between two variables, *x* and *y*. Given a value for one, we can use **(1)** to work out the value of the unknown. For instance, when *x=4*, *y=11*.

Differential equations are more general. They include __derivative terms__, denoted *dy/dx* or *y'*. Let us consider an example:

**(2)** *y' = dy/dx = ky*

While **(1)** described the relation between two variables, **(2)** describes the relation between *y*'s slope (with respect to *x*) and *y* itself. In English, it says that "*y*'s slope is directly proportional to *y*." Unlike **(1)**, the solution to **(2)** is a __function__ y, that satisfies the above description. But what kind of function has these properties? Let us solve **(2)** to find out:

* Take all the '*x*' terms to one side, and all the ‘*y’* terms to the other side:

*dy/dx = ky*

*dy = ky dx*

*dy/y = k dx*

*(1/y) dy = k dx*

* Take the integral of both sides (we omit some details about definite integrals and boundary conditions, for simplicity):

*INTEGRAL**( (1/y) dy) = **INTEGRAL**(k dx)*

* Evaluate the above integral:

*ln(y) = kx*

* Which is true if and only if:

*e*^{kx}* = y*

Thus we have shown that the exponential function *y(x) = e*^{kx} satisfies the differential equation **(2)**. This is what we should expect, since (2) said "*y*'s slope is directly proportional to *y*" and this is exactly how the number e is defined.

In further study, you will find that differential equations like **(2)** have applications in diverse fields such as: in Economics, to model growth rates and continuously compounded interest; Physics, to model radioactive decay or damped oscillations; in Biology to model bacteria populations. Now let us consider a more difficult example:

**(3)** ∂^{2}ψ/∂x^{2} = (1/v^{2})(∂^{2}ψ/∂t^{2})

**(3)** looks a little daunting but it is not much more complicated than **(2)**. The solution to **(3)** needs to be a function *ψ(x, t)*. *x* stands for a spatial direction, and *t* is time. *v* stands for ‘speed.’ We are given details about how *ψ*’s second (partial) derivatives, with respect to *x* and *t*, relate to each other. **(3)** is known to Physicists as the 'Wave Equation', because it can be derived by carefully studying springs in oscillation and sine/cosine waves like **(4)** are solutions to it.

**(4) ***ψ = Asin(kx - **ω**t**)*

Let us verify this.

* Calculate **(4)**’s second partial derivative with respect to *x* (we will need the Chain Rule):

**(5)** ∂^{2}ψ/∂x^{2}*= -k ^{2}*

* Calculate **(4)**’s second partial derivative with respect to *t*:

**(6)** ∂^{2}ψ/∂t^{2}*= -ω*^{2}*Asin(kx - **ω**t**)*

* We also need the following result (known as a dispersion relation). In physics, It can be shown that:

**(7)** *ω = kv*

where *ω* is ‘angular frequency’, *k* is ‘wavenumber’ and *v* is the speed that a wave propagates at.

* Substituting **(5)** and **(6)** into **(3) **gives:

*-k*^{2}*Asin(kx - **ω**t**) = -**(1/v*^{2}*)**ω*^{2}*Asin(kx - **ω**t**)*

*-k*^{2}* = -(1/v*^{2}*)**ω*^{2}

*k*^{2}*/**ω*^{2}* = 1/v*^{2}

*v*^{2}* = **ω*^{2}*/k*^{2}

*kv = **ω*

* Which we know to be correct because of result **(7)**, which follows from the definitions of ‘angular frequency’, ‘wavenumber’ and ‘wave speed’.

Hence the function *ψ(x, t) = Asin(kx - **ω**t**)* is a solution to the differential equation **(3)**. In fact, Schrödinger’s equation is a famous wave equation, incorporating complex numbers, whose solution is the ‘wavefunction’ of a system of particles. So I hope you can see, from this brief introduction, that we can get a lot of mileage out of this concept of ‘differential equations’!