Karan S. Uni Admissions Test Maths tutor, A Level Maths tutor, A Leve...

Karan S.

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Degree: Mathematics (Bachelors) - Cambridge University

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About me

About me:

I am a third year undergraduate at Cambridge University studying maths and physics. Whatever your age or ability, I look forward to helping you achieve and surpass your targets and gain a deeper understanding of the subject. 

Although throughout school I was usually able to grasp new concepts quickly, this meant that I spent a lot of time helping my peers and so have experience teaching the same material I will be teaching you.

The Sessions:

Naturally, the sessions will be tailored to you individually as everyone has their own preferred learning style and we will work together to find one that suits you and helps you progress the fastest.

Although I will primarily be helping you to improve your exam grades and understand the core material, I will also give you a deeper understanding of the underlying principles and concepts behind the material which I believe are very important to at least be aware of, even at earlier stages.

Finally, should you be considering studying maths at higher levels, I will be happy to help you decide whether it is for you and to assist with personal statements and university entrance if it is!

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Physics A Level £20 /hr
Chemistry GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
.STEP. Uni Admissions Test £25 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
Further MathsA-LevelA*
PhysicsA-LevelA*
MusicA-LevelA
STEP 3Uni Admissions Test1
STEP 2Uni Admissions Test1
Disclosure and Barring Service

CRB/DBS Standard

01/06/2013

CRB/DBS Enhanced

No

Currently unavailable: no new students

Questions Karan has answered

Given that y = x^4 + x^(1/3) + 3, find dy/dx

We use the rule that if y = x^n then dy/dx = n*x^(n-1) which is valid whether or not n is an integer.  We also use that differentiation is a linear operation, which means that we can differentiate term by term in the expression for y. Noting that 3 = 3*x^0, we therefore have dy/dx = 4*x^3 + ...

We use the rule that if y = x^n then dy/dx = n*x^(n-1) which is valid whether or not n is an integer. 

We also use that differentiation is a linear operation, which means that we can differentiate term by term in the expression for y.

Noting that 3 = 3*x^0, we therefore have

dy/dx = 4*x^3 + (1/3)*x^(-2/3) + 0

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1 year ago

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