Sahiththiyan S.

Sahiththiyan S.

£20 - £22 /hr

Mechanical Engineering MEng (Masters) - Imperial College London University

5.0
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

8 reviews

This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

18 completed lessons

About me

Hey! I am currently a student studying toward a MEng in Mechanical Engineering at Imperial College London. I am undertaking a placement year working for Jaguar Land Rover and have decided to begin tutoring online. I am capable of helping students studying Maths and Physics related subjects from Primary up to A Level standards. Being a student myself, I understand the importance of making lessons engaging and having the patience required for teaching. I hope that I will be able to pass on my experiences and knowledge to younger students yet to embark on their academical journey. Thank you!

Sahi Siva

Hey! I am currently a student studying toward a MEng in Mechanical Engineering at Imperial College London. I am undertaking a placement year working for Jaguar Land Rover and have decided to begin tutoring online. I am capable of helping students studying Maths and Physics related subjects from Primary up to A Level standards. Being a student myself, I understand the importance of making lessons engaging and having the patience required for teaching. I hope that I will be able to pass on my experiences and knowledge to younger students yet to embark on their academical journey. Thank you!

Sahi Siva

Show more

About my sessions

I believe that at the beginning of the session it is important to quickly recap the previous sessions and ask whether there are any doubts needed to be cleared. The remainder of the session will focus on any concerns raised, following on to the new content to be learned that lesson. Depending on the topic, I either begin with a small introduction (generally for a really new topic), or start with an example if it is a continuation from a previous topic. I found that learning through the practise of an example is very effective and engaging for students. After working with the student, I will be able to identify what their strengths and preferences are, and will take care to cater my teaching methods to suit them. I will close the lesson off with a summary of what was covered, recommend a few questions to practise and maybe some further reading, followed by anything they wish for me to cover in the next lesson.

I believe that at the beginning of the session it is important to quickly recap the previous sessions and ask whether there are any doubts needed to be cleared. The remainder of the session will focus on any concerns raised, following on to the new content to be learned that lesson. Depending on the topic, I either begin with a small introduction (generally for a really new topic), or start with an example if it is a continuation from a previous topic. I found that learning through the practise of an example is very effective and engaging for students. After working with the student, I will be able to identify what their strengths and preferences are, and will take care to cater my teaching methods to suit them. I will close the lesson off with a summary of what was covered, recommend a few questions to practise and maybe some further reading, followed by anything they wish for me to cover in the next lesson.

Show more

Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

No DBS Icon

No DBS Check

Ratings & Reviews

5
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
8 customer reviews
★ 5
8
★ 4
0
★ 3
0
★ 2
0
★ 1
0
FC
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Francis Parent from Birmingham Lesson review 11 Dec, 19:00

11 Dec

Good advice and understanding

JK
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Jenny Parent from Barnet

7 Dec

Sahiththiyan has been helping my son with his physics. We’ve noticed a real improvement in his physics work. Excellent tutor xx

FC
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Francis Parent from Birmingham Lesson review 29 Nov, 19:00

29 Nov

Got through a lot of content within the hour

FC
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Francis Parent from Birmingham Lesson review 30 Oct, 19:00

30 Oct

Good advice and ensures you do work

Show more reviews

Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
Further MathematicsA-level (A2)A*
Further Additional MathsA-level (AS)A
PhysicsA-level (A2)A*
ChemistryA-level (AS)A
TamilA-level (A2)A*

General Availability

MonTueWedThuFriSatSun
Pre 12pm
12 - 5pm
After 5pm

Pre 12pm

12 - 5pm

After 5pm
Mon
Tue
Wed
Thu
Fri
Sat
Sun

Subjects offered

SubjectQualificationPrices
MathsA Level£22 /hr
PhysicsA Level£22 /hr
MathsGCSE£20 /hr
PhysicsGCSE£20 /hr
Maths13 Plus£20 /hr
Personal StatementsMentoring£22 /hr

Questions Sahiththiyan has answered

Solve the following set of simultaneous equations: 3x + y = 11, 2x + y = 8

First I will explain the scenario and clearly describe what exactly the question is asking us to do: in this case, we have to find the correct value of 'x' and 'y' that successfully agree with both of the equations. Explain that, using one equation on its own gives an infinite number of possibilities for x and y values, but in order to satisfy both equations, there will only be one x and one y value. It is also important to note that the most effective and speed of method to solve simultaneous equations vary according to the question and the nature of the equations. For this example, method of Subtraction is the most obvious and easiest method, but I will show how using a different method such as substitution will give the same answer.Line up one equation above the other equation so that the x terms and y terms as well as the + and = signs line up. Show how when the 2x equation is subtracted from the 3x equation, you end up with x + (0y) = 3. We have calculated that x = 3. Substituting back x = 3 into any of the two equations will lead us to finding out what y is. It is wise to show how by using either equation you will end up with the same y equation, thus showing that x = 3 and y = 2 is a solution to both equations. I will further explore this topic, by drawing out the lines of both equations on a Cartesian graph and showing that the two lines intersect at one point, (3,2) as required.First I will explain the scenario and clearly describe what exactly the question is asking us to do: in this case, we have to find the correct value of 'x' and 'y' that successfully agree with both of the equations. Explain that, using one equation on its own gives an infinite number of possibilities for x and y values, but in order to satisfy both equations, there will only be one x and one y value. It is also important to note that the most effective and speed of method to solve simultaneous equations vary according to the question and the nature of the equations. For this example, method of Subtraction is the most obvious and easiest method, but I will show how using a different method such as substitution will give the same answer.Line up one equation above the other equation so that the x terms and y terms as well as the + and = signs line up. Show how when the 2x equation is subtracted from the 3x equation, you end up with x + (0y) = 3. We have calculated that x = 3. Substituting back x = 3 into any of the two equations will lead us to finding out what y is. It is wise to show how by using either equation you will end up with the same y equation, thus showing that x = 3 and y = 2 is a solution to both equations. I will further explore this topic, by drawing out the lines of both equations on a Cartesian graph and showing that the two lines intersect at one point, (3,2) as required.

Show more

4 months ago

74 views

Send Sahiththiyan a message

A Free Video Meeting is a great next step. Just ask Sahiththiyan below!


Send a message

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do Online Lessons work?

mtw:mercury1:status:ok