PremiumJonathan D. A Level Maths tutor, GCSE Physics tutor, GCSE Chemistry t...

Jonathan D.

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Natural Sciences (Physical) (Bachelors) - Cambridge University

5.0
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84 reviews

This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

176 completed lessons

About me

About Me: Having recently graduated in Natural Sciences (mostly physics) from the University of Cambridge, I am now spending my time helping others improve their own maths, physics and chemistry skills. I am massively passionate about all things Maths and Science, and I would love to be able to help you achieve success in either subject. The Session I am a firm believer that, when it comes to Maths and Science, having a really good understanding of the basic principles is more than half the battle! Personally I have always found past paper questions a great way of preparing for examinations and consolidating knowledge, so I will do my best to incorporate them into the sessions as and when. However, I am very flexible when it comes to the structure of the sessions: THE MOST IMPORTANT THING is that it works for you!!! If you have any questions, please feel free to ask! I would be delighted to answer them!

About Me: Having recently graduated in Natural Sciences (mostly physics) from the University of Cambridge, I am now spending my time helping others improve their own maths, physics and chemistry skills. I am massively passionate about all things Maths and Science, and I would love to be able to help you achieve success in either subject. The Session I am a firm believer that, when it comes to Maths and Science, having a really good understanding of the basic principles is more than half the battle! Personally I have always found past paper questions a great way of preparing for examinations and consolidating knowledge, so I will do my best to incorporate them into the sessions as and when. However, I am very flexible when it comes to the structure of the sessions: THE MOST IMPORTANT THING is that it works for you!!! If you have any questions, please feel free to ask! I would be delighted to answer them!

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About my sessions

In my two and a half years of tutoring experiences, I have found that what really helps most people is having the chance to talk through and clarify any ideas or concepts that they might be struggling with, and then consolidating this knowledge or understanding through a combination of carefully chosen examples, and questions from past exam papers which have been chosen either by me or you (or both) in advance. However, it is really important to acknowledge that everybody is different, and there is no 'universal approach'! I am more than happy to discuss with students exactly the sort of structure they would like the lessons to take, and we can adapt our approach from there accordingly in order to obtain the best possible results!

In my two and a half years of tutoring experiences, I have found that what really helps most people is having the chance to talk through and clarify any ideas or concepts that they might be struggling with, and then consolidating this knowledge or understanding through a combination of carefully chosen examples, and questions from past exam papers which have been chosen either by me or you (or both) in advance. However, it is really important to acknowledge that everybody is different, and there is no 'universal approach'! I am more than happy to discuss with students exactly the sort of structure they would like the lessons to take, and we can adapt our approach from there accordingly in order to obtain the best possible results!

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Ratings & Reviews

5from 84 customer reviews
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Ishtiaq (Parent from Hitchin)

April 19 2018

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Ishtiaq (Parent from Hitchin)

March 15 2018

Great tutor......both my boys (A Levels Physics / GCSE Maths) find Jonathan's teaching methods easy to understand. Grades beginning to reflect this at school.

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Sama (Parent from London)

February 4 2018

Very good and thorough at explaining concepts as well as being skilled at introducing and teaching question techniques.

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Adi (Student)

January 2 2017

Thank you Jonathan for getting Adi up to spped in Physics and achieving the B that he got!

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A*
PhysicsA-level (A2)A*
ChemistryA-level (A2)A*

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£26 /hr
PhysicsA Level£26 /hr
ChemistryGCSE£24 /hr
MathsGCSE£24 /hr
PhysicsGCSE£24 /hr

Questions Jonathan has answered

How do you find the equation of a tangent to a curve at a particular point?

Imagine being given the equation y=x3-2x+3, and being asked to find the tangent to the curve at the point where x=1.

The tangent to the curve will be a straight line, and therefore will take the form y=mx+c.

To find m (the gradient of the tangent), it is necessary first of all to differentiate the equation of the original curve. Doing this gives y’=3x2-2, where y’ is the gradient of the curve at a particular point. We are looking for the gradient at the point where x=1. Therefore, to find m, we must substitute x=1 into our expression. Doing so, we find that m=1.

We now know the equation of the tangent is y=x+c. To find c (the y-intercept), we must first of all know the coordinates of a point that the tangent is going to pass through. In our case, we know that the tangent must pass through the point on the line where x=1. To find the y-coordinate of this point, we can sub x=1 into our original equation of the curve. Doing so, we find that the point we must use is (1,2).

Now that we know a point on the line, we can sub those x and y values into the expression y=x+c. This gives us the equation 2=1+c, and some quick rearrangement shows us that c=1.

Therefore the equation of the tangent is y=x+1.

In summary:

-Equation of tangent is of the form y=mx+c

-To find m, differentiate the equation of the curve to find its gradient at the required point

-Find the coordinates of a point the tangent is going to pass through, and sub into the equation of the tangent to find c.

Imagine being given the equation y=x3-2x+3, and being asked to find the tangent to the curve at the point where x=1.

The tangent to the curve will be a straight line, and therefore will take the form y=mx+c.

To find m (the gradient of the tangent), it is necessary first of all to differentiate the equation of the original curve. Doing this gives y’=3x2-2, where y’ is the gradient of the curve at a particular point. We are looking for the gradient at the point where x=1. Therefore, to find m, we must substitute x=1 into our expression. Doing so, we find that m=1.

We now know the equation of the tangent is y=x+c. To find c (the y-intercept), we must first of all know the coordinates of a point that the tangent is going to pass through. In our case, we know that the tangent must pass through the point on the line where x=1. To find the y-coordinate of this point, we can sub x=1 into our original equation of the curve. Doing so, we find that the point we must use is (1,2).

Now that we know a point on the line, we can sub those x and y values into the expression y=x+c. This gives us the equation 2=1+c, and some quick rearrangement shows us that c=1.

Therefore the equation of the tangent is y=x+1.

In summary:

-Equation of tangent is of the form y=mx+c

-To find m, differentiate the equation of the curve to find its gradient at the required point

-Find the coordinates of a point the tangent is going to pass through, and sub into the equation of the tangent to find c.

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3 years ago

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