Mahfuza P.

Mahfuza P.

£22 - £26 /hr

Mechanical Engineering (Integrated Masters) - Leeds University

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This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

3 completed lessons

About me

I am a highly motivated university student studying mechanical engineering at The University of Leeds. I have always preferred design and science-based subjects to other subjects, so I chose A Levels that still left me a variety of paths to choose form. During my UCAS application, I didn’t know how to make such a big decision, I finally concluded that mechanical engineering was the degree for me as I prefer applying physics and maths to applications. I know how difficult it is to decide exactly what GCSE, A Level or degree to take so I am also here to give you any advice that you need.

I am a highly motivated university student studying mechanical engineering at The University of Leeds. I have always preferred design and science-based subjects to other subjects, so I chose A Levels that still left me a variety of paths to choose form. During my UCAS application, I didn’t know how to make such a big decision, I finally concluded that mechanical engineering was the degree for me as I prefer applying physics and maths to applications. I know how difficult it is to decide exactly what GCSE, A Level or degree to take so I am also here to give you any advice that you need.

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About my sessions

My first session with you will be free so I can get to know you (and vice versa) and what kind of extra help you are looking for and in which subject/s. I have tutored students for two years and they have seen a great difference in their grades. I am confident in my teaching methods as I can confidently translate complicated ideas into simple and memorable forms. I have collected various tips and tricks on how to revise different subjects and topics efficiently. I will set weekly personalised homework tasks and send lists of helpful online resources to you. Looking forward to hearing from you!

My first session with you will be free so I can get to know you (and vice versa) and what kind of extra help you are looking for and in which subject/s. I have tutored students for two years and they have seen a great difference in their grades. I am confident in my teaching methods as I can confidently translate complicated ideas into simple and memorable forms. I have collected various tips and tricks on how to revise different subjects and topics efficiently. I will set weekly personalised homework tasks and send lists of helpful online resources to you. Looking forward to hearing from you!

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A
ChemistryA-level (A2)A
PhysicsA-level (A2)B
PsychologyA-level (AS)A

General Availability

MonTueWedThuFriSatSun
Pre 12pm
12 - 5pm
After 5pm

Pre 12pm

12 - 5pm

After 5pm
Mon
Tue
Wed
Thu
Fri
Sat
Sun

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£24 /hr
MathsA Level£24 /hr
BiologyGCSE£22 /hr
ChemistryGCSE£22 /hr
Further MathematicsGCSE£22 /hr
MathsGCSE£22 /hr
Personal StatementsMentoring£24 /hr
MathsUniversity£26 /hr

Questions Mahfuza has answered

Express x^2+8x+15 in the form (x+a)^2-b

Completing the Square is required to solve this equation. First, identify A,B, and C of the quadratic equation: A=1, B=8, C=15. Halve B to obtain a: B/2 = 8/2 = 4 so a = 4. Substitute a into the form (x+a)2-b: (x+4)2-b. Square a because it is within the squared brackets: a2 = 42 =16. Subtract the square of a from the equation (x+4)2-b: (x+4)2-16. Add C to the equation to obtain the final answer: (x+4)2-16 +15 = (x+4)2-1. ANS=(x+4)2-1Completing the Square is required to solve this equation. First, identify A,B, and C of the quadratic equation: A=1, B=8, C=15. Halve B to obtain a: B/2 = 8/2 = 4 so a = 4. Substitute a into the form (x+a)2-b: (x+4)2-b. Square a because it is within the squared brackets: a2 = 42 =16. Subtract the square of a from the equation (x+4)2-b: (x+4)2-16. Add C to the equation to obtain the final answer: (x+4)2-16 +15 = (x+4)2-1. ANS=(x+4)2-1

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2 months ago

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