PremiumJoseph  E. GCSE Maths tutor, A Level Maths tutor

Joseph E.

Currently unavailable: for new students

Degree: Economics and Mathematics (Bachelors) - Bristol University

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About me

My name is Joe Eley and I am a recent graduate from the University of Bristol with a passion for tutoring and teaching. I studied for a joint honours in Mathematics and Economics, acheiving a 2:1. 

I have many hour of previous experience of teaching KS3, GCSE, AS and A2 level mathematics to a variety of students, of vastly different capabilities. I am confident that I will be able to help you increase your fundamental understanding of the work, promote your interest in the subject, and most importantly boost your grade.

I have a Level 2 Award in Mentoring for Young Learners from the Institute of Leadership and Management and have undertaken training in developing effective listening and questioning skills.

My approach is very structured to ensure optimum use of tutoring hours. After making sure the building blocks are in place, I will challenge the student with more advanced material to push them to achieve their potential.

For GCSE and A level tutoring, I provide a strong focus on exam technique and strategy, which I believe is very conducive to achieving learning outcomes, as well as increasing the student’s confidence for exam time.

In summary, if you are looking for a tutor that is enthusiastic, energetic and passionate about their subject, then look no further! I will provide a fun but focussed working environment and work tirelessly to ensure that learning outcomes are achieved. 

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
Economics and MathematicsBachelors Degree2:1
Mathematics A-LevelA
Geography A-LevelA
English Literature A-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for new students

Questions Joseph has answered

Differentiate y=(4x - 5)^5 by using the chain rule.

Notation: I use the ^ in the title question to indicated 'to the power of' and I use an asterisk * (or star) to indicate 'multiplied by' in the answer, to avoid confusion with the x term!  Step 1) let u = 4x - 5      therefore y = u5 Step 2) du/dx = 4           dy/du = 5u4 Step 3) (the chain...

Notation: I use the ^ in the title question to indicated 'to the power of' and I use an asterisk * (or star) to indicate 'multiplied by' in the answer, to avoid confusion with the x term! 

Step 1) let u = 4x - 5      therefore y = u5

Step 2) du/dx = 4           dy/du = 5u4

Step 3) (the chain rule!)  dy/dx = dy/du * du/dx

so dy/dx = 5u4 * 4

     dy/dx = 20u4 

     dy/dx = 20(4x - 5)4 as we substitute for the u term to complete our answer! 

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1 year ago

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