Nishit B.

Currently unavailable: for regular students

Degree: Engineering (Masters) - Oxford, New College University

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Hello! I am a second year Engineering undergraduate at the University of Oxford. I am happy to help with A-level/GCSE Maths.

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Maths A Level £20 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
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MathematicsA-LevelA*
Further MathematicsA-LevelA
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ChemistryA-LevelA
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### If y = (1+3x)^2, what is dy/dx?

A good approach to solve this is to use the chain rule of differentiation. The chain rule states: dy/dx= (dy/du)*(du/dx). In this case let u = 1+3x, so y = u^2. Then dy/du = 2u and du/dx = 3, so dy/dx = (2u)*3 = (2(1+3x))*3 = 6+18x

A good approach to solve this is to use the chain rule of differentiation. The chain rule states: dy/dx= (dy/du)*(du/dx).

In this case let u = 1+3x, so y = u^2.

Then dy/du = 2u and du/dx = 3,

so dy/dx = (2u)*3 = (2(1+3x))*3 = 6+18x

12 months ago

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