Nishit B. A Level Maths tutor, GCSE Maths tutor, A Level Further Math...

Nishit B.

£18 - £22 /hr

Currently unavailable: for regular students

Studying: Engineering (Masters) - Oxford, New College University

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About me

Hello! I am a second year Engineering undergraduate at the University of Oxford. I am happy to help with A-level/GCSE Maths.

Hello! I am a second year Engineering undergraduate at the University of Oxford. I am happy to help with A-level/GCSE Maths.

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A
PhysicsA-level (A2)A
ChemistryA-level (A2)A

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr
PhysicsGCSE£18 /hr
Maths13 Plus £18 /hr
-Personal Statements-Mentoring£22 /hr

Questions Nishit has answered

If y = (1+3x)^2, what is dy/dx?

A good approach to solve this is to use the chain rule of differentiation. The chain rule states: dy/dx= (dy/du)*(du/dx).

In this case let u = 1+3x, so y = u^2.

Then dy/du = 2u and du/dx = 3,

so dy/dx = (2u)*3 = (2(1+3x))*3 = 6+18x

A good approach to solve this is to use the chain rule of differentiation. The chain rule states: dy/dx= (dy/du)*(du/dx).

In this case let u = 1+3x, so y = u^2.

Then dy/du = 2u and du/dx = 3,

so dy/dx = (2u)*3 = (2(1+3x))*3 = 6+18x

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1 year ago

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