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About me

About me

I’m a first year student studying Maths with European Studies at Durham. I have recently taken my A levels, achieving A* in Maths and Further Maths, so I am familiar with the course content and what the examiners are looking for in answers and can help you achieve the top grades.  In the past I have helped friends at GCSE and A level, including leading group A-level Maths revision sessions. I am enthusiastic about all the subjects I offer and I hope I can impart some of that enthusiasm on to you.

The session

I aim to use a variety of teaching methods, including past paper questions and diagrams to promote engagement and enhance learning so that you get the most out of your session. Everyone learns differently so I believe that it is important to tailor the pace and content of the session to you, with specific focus being placed on the areas which you feel unsure about and wish to improve upon.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £24 /hr
Maths A Level £24 /hr
Maths GCSE £22 /hr
Physics GCSE £22 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
Further MathsA-LevelA*
PhysicsA-LevelA
FrenchA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Ratings and reviews

5from 103 customer reviews

Anujin (Student) October 12 2016

Thanks again!

Anujin (Student) October 20 2016

Another great tutorial, thank you very much!

Mrs E (Parent) June 25 2016

AAA++++

Mrs E (Parent) June 19 2016

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Questions Daniel has answered

How do I express y=acosx+bsinx in the form y=Rcos(x-c)?

From the addition formula, we know that: Rcos(x-c) = Rcos(x)sin(c)+Rsin(x)cos(c) Therefore: acos(x)+bsin(x) = Rcos(x)cos(c)+Rsin(x)sin(c) If we equate the coefficients of cos(x) and sin(x) we see that: acos(x) = Rcos(x)sin(c);   therefore a = Rcos(c) And that: bsin(x) = Rsin(x)cos(c);    t...

From the addition formula, we know that:

Rcos(x-c) = Rcos(x)sin(c)+Rsin(x)cos(c)

Therefore:

acos(x)+bsin(x) = Rcos(x)cos(c)+Rsin(x)sin(c)

If we equate the coefficients of cos(x) and sin(x) we see that:

acos(x) = Rcos(x)sin(c);   therefore a = Rcos(c)

And that:

bsin(x) = Rsin(x)cos(c);    therefore b = Rsin(c)

To find c:

If we divide one of the above results by the other:

Rsin(c)/Rcos(c) = b/a

Rsin(c)/Rcos(c) = b/a

tan(c) = b/a

Therefore, c = arctan(b/a)

To find R:

a2+b2 = R2cos2(c)+R2sin2(c)

a2+b2 = R2(cos2(c)+sin2(c))

As cos2(c)+sin2(c) = 1,

a2+b2 = R2

(a2+b2)1/2=R

So, overall:

acos(x)+bsin(x) = (a2+b2)1/2cos(x-arctan(b/a))

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1 year ago

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