PremiumHannah M. A Level Maths tutor, GCSE Maths tutor, 11 Plus Maths tutor

Hannah M.

£24 - £26 /hr

Mathematics with Year Abroad (Bachelors) - Durham University

5.0
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35 reviews

132 completed lessons

Message Hannah

About me

Hi, I'm Hannah and I am studying Maths in my third year at Durham University, although I am currently on a year abroad at Granada University, Spain. I really loved maths all the way through school and university and have signed up to be a tutor so I can try to share that love with others! I have lots of expereince as a tutor with mytutor.co.uk, and have helped many students progress greatly with their maths, as well as helping them to achieve good grades in their exams. I can also help with GCSE level maths, and I can give Spanish speaking classes, given that I have now been living in Spain for 6 months. I am very patient and I will always try to come up with different ways of looking at concepts if they don't make sense at first. I also hope to make my tutorials enjoyable, as well as educational. Please don't hesitate to contact me if you would like to organise a free 15 minute "meet the tutor" session to get to know me. I've posted the hours I'm usually free below, however my timetable is quite flexible, so I am willing to try and work around you. I hope to be meeting you soon!

Hi, I'm Hannah and I am studying Maths in my third year at Durham University, although I am currently on a year abroad at Granada University, Spain. I really loved maths all the way through school and university and have signed up to be a tutor so I can try to share that love with others! I have lots of expereince as a tutor with mytutor.co.uk, and have helped many students progress greatly with their maths, as well as helping them to achieve good grades in their exams. I can also help with GCSE level maths, and I can give Spanish speaking classes, given that I have now been living in Spain for 6 months. I am very patient and I will always try to come up with different ways of looking at concepts if they don't make sense at first. I also hope to make my tutorials enjoyable, as well as educational. Please don't hesitate to contact me if you would like to organise a free 15 minute "meet the tutor" session to get to know me. I've posted the hours I'm usually free below, however my timetable is quite flexible, so I am willing to try and work around you. I hope to be meeting you soon!

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About my sessions

My online lessons vary greatly from student to student, depending on their needs. I feel the best way to progress with Maths is through lots of examples, so in a typical lesson I would introduce a new topic, before proceeding to go through plenty of examples. To make the most of the tutorials it is key that the student look through the material in their own time too, so I will set tasks to do away from the tutorial to further develop their skills. Alternatively, I use my tutorials to help students with any schoolwork they're struggling with, as well as going through past papers in the weeks leading up to exams. I always try to form a friendly relationship with my students, so the tutorials can be more enjoyable, as I think it is much easier to learn when you're enjoying yourself!

My online lessons vary greatly from student to student, depending on their needs. I feel the best way to progress with Maths is through lots of examples, so in a typical lesson I would introduce a new topic, before proceeding to go through plenty of examples. To make the most of the tutorials it is key that the student look through the material in their own time too, so I will set tasks to do away from the tutorial to further develop their skills. Alternatively, I use my tutorials to help students with any schoolwork they're struggling with, as well as going through past papers in the weeks leading up to exams. I always try to form a friendly relationship with my students, so the tutorials can be more enjoyable, as I think it is much easier to learn when you're enjoying yourself!

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Ratings & Reviews

5from 35 customer reviews
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Roisin (Student)

May 4 2016

Really helpfull and clear on the solutions to questions.

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Denisse (Parent from Studley)

April 16 2016

Thank you Hannah - Natalia enjoyed her tutorial with you

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Roisin (Student)

April 4 2016

Very nice and taught in logical steps which was helpful when I got stuck on parts of the question.

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Farah (Student)

April 25 2018

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A*
ChemistryA-level (A2)A*
SpanishA-level (A2)A

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£26 /hr
MathsA Level£26 /hr
Further MathematicsGCSE£24 /hr
MathsGCSE£24 /hr
SpanishGCSE£24 /hr
Career DevelopmentMentoring£26 /hr

Questions Hannah has answered

Prove that 1/(tanx) + tanx = 1/sinxcosx

The key here is to realise that tanx = sinx/cosx. If we write out the left hand side of the equation in terms of sine and cosine we get: cosx/sinx + sinx/cosx These two fractions can be put over a common denominator of sinxcosx to give: (cos2x + sin2x)/sinxcosx If we then use the well-known identity cos2x + sin2x = 1, we see that the above expression is equivalent to 1/sinxcosx, which is the expression we were required to find. The key here is to realise that tanx = sinx/cosx. If we write out the left hand side of the equation in terms of sine and cosine we get: cosx/sinx + sinx/cosx These two fractions can be put over a common denominator of sinxcosx to give: (cos2x + sin2x)/sinxcosx If we then use the well-known identity cos2x + sin2x = 1, we see that the above expression is equivalent to 1/sinxcosx, which is the expression we were required to find.

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2 years ago

6656 views

Solve the equation 5^x = 8, giving your answer to 3 significant figures.

Since there is an x written as a power here, it suggests that this question should be solved using logs (here assume I am using the natural logarithm, which has base e). Taking logs of both sides of the equation gives log5x = log8 Using the rule logab = bloga, the equation becomes xlog5 = log8 If we then divide the equation through by log5, we see that x = log8/log5 = 1.29 Since there is an x written as a power here, it suggests that this question should be solved using logs (here assume I am using the natural logarithm, which has base e). Taking logs of both sides of the equation gives log5x = log8 Using the rule logab = bloga, the equation becomes xlog5 = log8 If we then divide the equation through by log5, we see that x = log8/log5 = 1.29

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2 years ago

1514 views

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