Victor A. A Level Biology tutor, A Level Chemistry tutor, A Level -Pe...

Victor A.

Currently unavailable: for regular students

Degree: Biological Sciences (Bachelors) - Oxford, Merton College University

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About me

Hello!

About me

I have just completed my first year studying Biological Sciences at Merton College Oxford and have had a wonderful time integrating Maths, Chemistry and Biology to understand living things. I am a personable and enthusiastic student with a genuine passion for science and teaching.

I'm particularly excited to share my fascination of the natural world with younger students while preparing them exceptionally for exams so that they can realise their potential and possible dreams of studying at a top university.

The sessions

My lessons will focus on areas where students have a weak understanding and where there are gaps in their knowledge.  This means that you get what you want most out of sessions.

learning the content given by the exam board specification to the highest standard and then tackling exam questions is key to success and this will form the framework of lessons. I am always happy to explain things in different ways and to take as much time as necessary so that students have an excellent understanding of topics.

I have always learnt best where a teacher is receptive, patient and understanding. I always strive to ensure that a student feels like they can ask any question they want and that it's okay to make mistakes. This way students can learn to have confidence in their answers and areas for improvement can be quickly identified.

Can you help me out with my Personal Statement and Oxbridge interviews??

I would love to!  I remember how painful drafting and redrafting my personal statement was, so I will do my best to ensure that when you draft yours It will be as stress-free as possible. I also remember how nerve wracking the run up to my Oxford interviews were. I hope the advice and prep I give will help you walk into your interviews with calm confidence.

What’s next?

If you’d like to get in contact with me to ask any questions just send me a ‘WebMail’ or book a ‘Meet the Tutor Session’ (on this website). If you could let me know what you need help with that would be great.

See you soon!

Subjects offered

SubjectLevelMy prices
Biology A Level £20 /hr
Chemistry A Level £20 /hr
Biology GCSE £18 /hr
Chemistry GCSE £18 /hr
Maths GCSE £18 /hr
-Personal Statements- Mentoring £20 /hr

Qualifications

QualificationLevelGrade
BiologyA-LevelA*
ChemistryA-LevelA*
Physics A-LevelA*
MathsA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

27/04/2015

Currently unavailable: for regular students

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Questions Victor has answered

A titration is carried out and 0.04dm^3 of sulphuric acid neutralises 0.08dm^3 sodium hydroxide of concentration 1mol/dm^3. Calculate the concentration of the sulphuric acid.

The first thing to do with this titration calculation is write the balanced symbol equation for the reaction. Using the knowlege that when an acid and base react a salt and water is produced we can write: H2SO4 (aq)+ 2NaOH (aq) ---> Na2SO4 (aq)+ 2H2O (l) From the balanced symbol equation we c...

The first thing to do with this titration calculation is write the balanced symbol equation for the reaction. Using the knowlege that when an acid and base react a salt and water is produced we can write:

H2SO4 (aq)+ 2NaOH (aq) ---> Na2SO4 (aq)+ 2H2(l)

From the balanced symbol equation we can see that 1 mole of H2SO4 neutralises 2 moles of NaOH

The next thing to do is calculate the number of moles of sodium hydroxide that were used up in the reaction.

We use the equation: number of moles = concentration x volume

N =    1 mol/dm3   x 0.08dm3 = 0.08 moles of NaOH

The number of moles of H2SO4 used up in the reaction is therefore half of this (0.04 moles) since we established from the symbol equation that 1 mole of H2SO4 neutralises 2 moles of NaOH.

Finally we can calculate the concentration of H2SO4 by using the equation :

concentration = number of moles/ volume

c = 0.04mol/ 0.04dm3 = 1mol/dm3
 

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5 months ago

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Describe how Carbon Dioxide is assimilated in the Calvin cycle.

CO2 from the atmosphere diffuses into the leaf through the stomata and then into the stroma within the chloroplasts of mesophyll cells.  In the stroma the enzyme Ribusco catalyes the combining of CO2 with ribulose bisphosphate to form an intermediate which breaks down into two glycerate -3-pho...

CO2 from the atmosphere diffuses into the leaf through the stomata and then into the stroma within the chloroplasts of mesophyll cells.  In the stroma the enzyme Ribusco catalyes the combining of CO2 with ribulose bisphosphate to form an intermediate which breaks down into two glycerate -3-phosphate molecules. The hydrolysis of ATP ( produced in the light dependent reaction) releases energy which is used to reduce glycerate -3 - phoshpate into triose phosphate. The reductant NADPH is oxidised to regenreate NAPD+ which is again able to accept hydrogen from the photolysis of water. Some triose phosphate molecules are used to produce useful organic substances like glucose while most are used to regenerate ribulose bisphosphate.

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5 months ago

170 views
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