Iris-Ioana R.

Iris-Ioana R.

£18 - £25 /hr

Mathematics (Integrated Masters) - Imperial College London University

5.0
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4 reviews

This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

7 completed lessons

About me

Hi!

My name is Iris and I am a first-year Mathematics student at Imperial College London. As most of my life revolved around Maths, I can say that this subject defines my personality and I would love to share my passion with others aswell. I am originally from Romania, where I managed to score full marks in the Romanian Baccalaureate exams.


My interest in the intriguing World of Numbers pushed me towards Olympiads where I managed to qualify eight consecutive years for the National Phase, in five of them winning a Bronze Medal. I have always had a desire for a deeper understanding of Mathematics this resulting in my participation in various mathematical camps. There I had the opportunity to prepare some advanced lectures for some brilliant students from all over my country. Apart from that, I have voluntarily tutored children from orphanages managing to visibly improve their grades and to engage their curiosity regarding Maths.

Hi!

My name is Iris and I am a first-year Mathematics student at Imperial College London. As most of my life revolved around Maths, I can say that this subject defines my personality and I would love to share my passion with others aswell. I am originally from Romania, where I managed to score full marks in the Romanian Baccalaureate exams.


My interest in the intriguing World of Numbers pushed me towards Olympiads where I managed to qualify eight consecutive years for the National Phase, in five of them winning a Bronze Medal. I have always had a desire for a deeper understanding of Mathematics this resulting in my participation in various mathematical camps. There I had the opportunity to prepare some advanced lectures for some brilliant students from all over my country. Apart from that, I have voluntarily tutored children from orphanages managing to visibly improve their grades and to engage their curiosity regarding Maths.

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About my sessions

The goal of my teaching is not only improving grades but also boosting confidence and descovering the beauty of Maths. The structure of my lessons will be flexible depending on my tutee's needs and best learning style. I will adapt my sessions based on the weeknesses and I will come up with challenging and interesting exercises for every level that could arise the interest towards this subject. My sessions will include a lot of questions that could verify the tutee's understanding of methods or tricks explained before.

The goal of my teaching is not only improving grades but also boosting confidence and descovering the beauty of Maths. The structure of my lessons will be flexible depending on my tutee's needs and best learning style. I will adapt my sessions based on the weeknesses and I will come up with challenging and interesting exercises for every level that could arise the interest towards this subject. My sessions will include a lot of questions that could verify the tutee's understanding of methods or tricks explained before.

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Ratings & Reviews

5
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4 customer reviews
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Daniela Student Lesson review 6 Dec, 16:00

6 Dec

Really clear explanations, I enjoyed doing the exercises as they were helpful and Iris-Iona was there to help me when I was stuck and made sure I fully understood the material. Thank you very much! Looking forwards to the next session!

AR
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Aaliyah Student Lesson review 28 Nov, 15:00

28 Nov

She goes step by step in detail and explain the concepts really well.

AC
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Alison Parent from Lincoln Lesson review 5 Dec, 17:00

5 Dec

CD
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Céline Student Lesson review 2 Dec, 16:00

2 Dec

Qualifications

SubjectQualificationGrade
Further MathematicsRomanian Baccalaureate10/10
ComputingRomanian Baccalaureate10/10
Romanian Language and LiteratureRomanian Baccalaureate10/10

General Availability

MonTueWedThuFriSatSun
Pre 12pm
12 - 5pm
After 5pm

Pre 12pm

12 - 5pm

After 5pm
Mon
Tue
Wed
Thu
Fri
Sat
Sun

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£20 /hr
MathsA Level£20 /hr
Further MathematicsGCSE£18 /hr
MathsGCSE£18 /hr
Further MathematicsIB£20 /hr
MathsIB£20 /hr
Maths13 Plus£18 /hr
Maths11 Plus£18 /hr
MATUniversity£25 /hr

Questions Iris-Ioana has answered

Find  ∫(2x^5 - 1/(4x^3) - 5)dx giving each term in its simplest form.

Firstly, we can rewrite 1/(4x3) as 1/4 x-3. Therefore, I can write the integral as a sum of integrals ∫(2x5 - 1/(4x3) - 5)dx=2 ∫x5dx-1/4 ∫x-3 dx-5 ∫dx. Using the general formula: ∫ xndx=xn+1/(n+1) + C for all real n, n not equal to -1, we have: ∫x5 dx= x6/6 + C, ∫ x-3 dx= x-2/-2 + C and ∫x0 dx=x1/1 + C. So, ∫(2x5 - 1/(4x3) - 5)dx = 2/6 x6-1/(-2)4 x-2 - 5x +C=x6/3+1/(8x2)- 5x+C.Firstly, we can rewrite 1/(4x3) as 1/4 x-3. Therefore, I can write the integral as a sum of integrals ∫(2x5 - 1/(4x3) - 5)dx=2 ∫x5dx-1/4 ∫x-3 dx-5 ∫dx. Using the general formula: ∫ xndx=xn+1/(n+1) + C for all real n, n not equal to -1, we have: ∫x5 dx= x6/6 + C, ∫ x-3 dx= x-2/-2 + C and ∫x0 dx=x1/1 + C. So, ∫(2x5 - 1/(4x3) - 5)dx = 2/6 x6-1/(-2)4 x-2 - 5x +C=x6/3+1/(8x2)- 5x+C.

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1 month ago

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