Iris-Ioana R.

Iris-Ioana R.

£22 - £26 /hr

Mathematics (Integrated Masters) - Imperial College London University

5.0
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29 reviews

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44 completed lessons

About me

Hi!

My name is Iris and I am a first-year Mathematics student at Imperial College London. As most of my life revolved around Maths, I can say that this subject defines my personality and I would love to share my passion with others aswell. I am originally from Romania, where I managed to score full marks in the Romanian Baccalaureate exams.


My interest in the intriguing World of Numbers pushed me towards Olympiads where I managed to qualify eight consecutive years for the National Phase, in five of them winning a Bronze Medal. I have always had a desire for a deeper understanding of Mathematics this resulting in my participation in various mathematical camps. There I had the opportunity to prepare some advanced lectures for some brilliant students from all over my country. Apart from that, I have voluntarily tutored children from orphanages managing to visibly improve their grades and to engage their curiosity regarding Maths.

Hi!

My name is Iris and I am a first-year Mathematics student at Imperial College London. As most of my life revolved around Maths, I can say that this subject defines my personality and I would love to share my passion with others aswell. I am originally from Romania, where I managed to score full marks in the Romanian Baccalaureate exams.


My interest in the intriguing World of Numbers pushed me towards Olympiads where I managed to qualify eight consecutive years for the National Phase, in five of them winning a Bronze Medal. I have always had a desire for a deeper understanding of Mathematics this resulting in my participation in various mathematical camps. There I had the opportunity to prepare some advanced lectures for some brilliant students from all over my country. Apart from that, I have voluntarily tutored children from orphanages managing to visibly improve their grades and to engage their curiosity regarding Maths.

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About my sessions

The goal of my teaching is not only improving grades but also boosting confidence and descovering the beauty of Maths. The structure of my lessons will be flexible depending on my tutee's needs and best learning style. I will adapt my sessions based on the weeknesses and I will come up with challenging and interesting exercises for every level that could arise the interest towards this subject. My sessions will include a lot of questions that could verify the tutee's understanding of methods or tricks explained before.

The goal of my teaching is not only improving grades but also boosting confidence and descovering the beauty of Maths. The structure of my lessons will be flexible depending on my tutee's needs and best learning style. I will adapt my sessions based on the weeknesses and I will come up with challenging and interesting exercises for every level that could arise the interest towards this subject. My sessions will include a lot of questions that could verify the tutee's understanding of methods or tricks explained before.

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Enhanced DBS Check

31/01/2019

Ratings & Reviews

5
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29 customer reviews
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IJ
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Irene Parent from London

9 Feb

I find her lessons to be extremely well planned, she always asks you what you want to study, and then she structures the lesson in such a way that the topic is fully understood by the end.

MT
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M Parent from Kettering

8 Feb

Iris clearly explained challenging further maths examples by going through each question methodically and linking to the basics. It helped me thoroughly!

AC
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Alison Parent from Lincoln

14 Jan

Iris is very receptive to my daughters ability and challenges her at the right level.

SB
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Stefan Parent from LONDON Lesson review 5 Jan, 22:00

5 Jan

Insightful help, would recommend

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Qualifications

SubjectQualificationGrade
Further MathematicsRomanian Baccalaureate10/10
ComputingRomanian Baccalaureate10/10
Romanian Language and LiteratureRomanian Baccalaureate10/10

General Availability

MonTueWedThuFriSatSun
Pre 12pm
12 - 5pm
After 5pm

Pre 12pm

12 - 5pm

After 5pm
Mon
Tue
Wed
Thu
Fri
Sat
Sun

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£24 /hr
MathsA Level£24 /hr
Further MathematicsGCSE£22 /hr
MathsGCSE£22 /hr
Further MathematicsIB£24 /hr
MathsIB£24 /hr
Maths13 Plus£22 /hr
Maths11 Plus£22 /hr
MATUniversity£26 /hr

Questions Iris-Ioana has answered

Find  ∫(2x^5 - 1/(4x^3) - 5)dx giving each term in its simplest form.

Firstly, we can rewrite 1/(4x3) as 1/4 x-3. Therefore, I can write the integral as a sum of integrals ∫(2x5 - 1/(4x3) - 5)dx=2 ∫x5dx-1/4 ∫x-3 dx-5 ∫dx. Using the general formula: ∫ xndx=xn+1/(n+1) + C for all real n, n not equal to -1, we have: ∫x5 dx= x6/6 + C, ∫ x-3 dx= x-2/-2 + C and ∫x0 dx=x1/1 + C. So, ∫(2x5 - 1/(4x3) - 5)dx = 2/6 x6-1/(-2)4 x-2 - 5x +C=x6/3+1/(8x2)- 5x+C.Firstly, we can rewrite 1/(4x3) as 1/4 x-3. Therefore, I can write the integral as a sum of integrals ∫(2x5 - 1/(4x3) - 5)dx=2 ∫x5dx-1/4 ∫x-3 dx-5 ∫dx. Using the general formula: ∫ xndx=xn+1/(n+1) + C for all real n, n not equal to -1, we have: ∫x5 dx= x6/6 + C, ∫ x-3 dx= x-2/-2 + C and ∫x0 dx=x1/1 + C. So, ∫(2x5 - 1/(4x3) - 5)dx = 2/6 x6-1/(-2)4 x-2 - 5x +C=x6/3+1/(8x2)- 5x+C.

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3 months ago

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