Dominic M. GCSE Maths tutor, A Level Maths tutor

Dominic M.

Currently unavailable: no new students

Degree: Aeronautical Engineering (Masters) - Bristol University

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About me

Hi I’m Dom, I study Aerospace Engineering at Bristol University. I really enjoy Maths & Physics and I hope this passion will come out in our sessions. 

Maths & Physics are like a Jenga towers. Often if one brick is dislodged it will make it difficult to understand new concepts and reach new heights. I can go over any topic to ensure your foundations are solid. This is improtant before you move onto the more difficult concepts that prop up at GCSE & A-level. 

Before university I was a Scout Leader where I taught the troop basic aircraft design, they then designed & built their own wind up models. I believe it is important to relate subjects back to real world situations at every stage to keep them interesting and engaging. If you tell me your interests I can do this for you. 

I have applied this during my own university career, I am just starting my 3rd year and have already spent 18 months with some of the largest British aerospace companies

If you have any questions please send me a "Webmail". I look forward to hearing from you.

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA
Further MathsA-LevelA*
Additional Further Maths (AS Only)A-LevelA
PhysicsA-LevelB
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: no new students

Questions Dominic has answered

Factorise and solve x^2 - 8x + 15 = 0.

The easiest way to solve this problems it via trial and error. For any quatdratic (ax2 + bx  + C = 0), the coeficcent of x, (in this case b = 8) is the sum(+) of the two solutions and c is the product(*). So you need to find two numbers that add to give -8 and multiply to give 15. In this case...

The easiest way to solve this problems it via trial and error. For any quatdratic (ax2 + bx  + C = 0), the coeficcent of x, (in this case b = 8) is the sum(+) of the two solutions and c is the product(*). So you need to find two numbers that add to give -8 and multiply to give 15. In this case it is -3 and -5 as -3+-5=-8 and -3*-5=15. This measn the answer is (x-3)(x-5) = 0, so x= 3, or 5. 

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1 year ago

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