Patrick M. GCSE Maths tutor, Mentoring Maths tutor

Patrick M.

Currently unavailable: no new students

Degree: Aerospace Engineering (MEng) (Masters) - Bristol University

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About me

Hello there! 

I'm a third year Aerospace Engineering student at the University of Bristol. During school I was part of a mentoring scheme for younger students and since completing my A-Levels I've taken up regular one-to-one tutoring in Maths.

Whether it's understanding the key concepts or preparing for an upcoming exam, I'll use a variety of different techniques to help you become confident in the subject area, using frequent examples to back-up the theory. I believe the key to successful tutoring is letting the student decide what topics they wish to cover in the session, based on what they feel least confident in.

I am flexible across all the major exam boards (AQA, Edexcel, OCR etc) and have experience tutoring the iGCSE courses as well. 

If you're interested, please get in touch to arrange a free meet-the-tutor session!    

Thanks, Patrick :)

Subjects offered

SubjectLevelMy prices
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
Further MathsA-LevelA*
PhysicsA-LevelA*
Design and TechnologyA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: no new students

Questions Patrick has answered

What is the quadratic formula and how do I use it?

The quadratic formula is a way of solving quadratic equations of the form: ax2 +bx+c=0. By plugging in the values a,b and c into it, the solutions for x can be obtained: x = [-b +/- sqrt(b2-4ac)]/2a  For example, solving 2x2+3x-5=0: a = 2, b = 3, c = -5 so inputting these values into the form...

The quadratic formula is a way of solving quadratic equations of the form: ax2+bx+c=0. By plugging in the values a,b and c into it, the solutions for x can be obtained:

x = [-b +/- sqrt(b2-4ac)]/2a 

For example, solving 2x2+3x-5=0:

a = 2, b = 3, c = -5 so inputting these values into the formula above:

x = [-3 +/- sqrt(32-4(2*-5)]/(2*2)

x = 1 or x = -5/2

These can be checked by inserting them into the original equation, or using a graphical method looking at the x-intercept coordinates.

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1 year ago

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