Kara  V. GCSE Maths tutor, GCSE Science tutor, A Level Maths tutor, A...

Kara V.

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Degree: Evolutionary Anthropology (Masters) - Durham University

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About me

About me:

I am currently at Durham studying for a Masters in Anthropology, after just completing my Masters in Physics at the University of York.

I am looking to teach a bit of maths and science to GCSE and A level student of all abilities. I am the oldest of about 15 cousins, and have tutored most of them at some point or another, for that final exam where they needed that C, or sometimes for just a confidence boost, to get them on the right track again. I think that my patience, reassuring attitude and my terrible humour has really helped me with this. 

I think that because maths and science can be seen as such difficult subjects, a lot of students give up so readily that they can miss out on the opportunity of discovering how interesting and satisfying they can be to study. I really hope that my tutoring can help to spark that interest, particularly for girls who might not otherwise think about persuing science and maths at higher levels. 

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Physics A Level £20 /hr
Chemistry GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
Science GCSE £18 /hr

Qualifications

QualificationLevelGrade
PhysicsMasters Degree1st
MathsA-LevelA*
PhysicsA-LevelA
Further MathsA-LevelB
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: no new students

Questions Kara has answered

Two points have coordinates (1,-6) and (-2,3). Find the equation of the line which joins them, and their midpoint.

To find the line's equation, you need the gradient and the y-intercept. The gradient is found using: (y2-y1)/(x2-x1) Or simply (change in y direction)/(change in x direction) In this case, the gradient =(3+6)/(-2-1)=9/-3=-3 and so the equation of the line is in the form  y=-3x+c We now nee...

To find the line's equation, you need the gradient and the y-intercept. The gradient is found using:

(y2-y1)/(x2-x1)

Or simply (change in y direction)/(change in x direction)

In this case, the gradient =(3+6)/(-2-1)=9/-3=-3

and so the equation of the line is in the form 

y=-3x+c

We now need to find the y-intercept, or 'c' in the equation above.

All points on this line will follow this equation. This includes the two points in the question, so we can sub in the x and y values and rearrange to find c. We can choose either of the points. Lets start with (1,-6)

x=1, y=-6

y=-3x + c

-6=-3*1 +c

-6=-3 +c

c=-3

Therefore:

y=-3x-3

We can check this by using the other coordinate:

(-2,3) 

x=-2, y=3

3=-3*-2  -3

3=6-3

3=3

As for finding the midpoint of the two points, we just need to find middle of the 2 x-coordinates and the middle of the 2 y-coordinates (need some diagrams here)

To do this, we can just find the averages.

x - coordinates: 1 and -2

x midpoint = (1+ -2)/2 = -0.5

y - coordinates: -6 and 3

y midpoint = (-6+3)/2 =-1.5

So our midpoint coordinate is (-0.5, -1.5)

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1 year ago

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