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About me

Hi, my name is Hayden. I am a high-performing 3rd year Physics student at The University of Warwick. I get excited about all things science and I hope that I can help you not only learn your material but also understand why it is a useful thing to know.

As a person, I am very relaxed. Hence, if you tend to get stressed out when you don't understand something, I'm sure we can balance each other out and figure out a way to make it 'click'.

As for what you want to be taught: that's up to you. Exam questions, lesson-like explanations of theory, helping you work through some homework - you decide and I'll do my best to help.

Still not convinced? Book a free 'meet the tutor' session with me to get a feel for my personality and teaching style. I look forward to meeting with you, thanks.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £22 /hr
Maths A Level £22 /hr
Physics A Level £22 /hr
Chemistry GCSE £20 /hr
English GCSE £20 /hr
Maths GCSE £20 /hr
Physics GCSE £20 /hr
Science GCSE £20 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
PhysicsA-LevelA*
ChemistryA-LevelA
Further MathematicsA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

5from 17 customer reviews

Ryuko (Parent) October 1 2016

Very good first session. It was clear and easy to follow. Thank you.

Ryuko (Parent) November 27 2016

Ryuko (Parent) November 27 2016

Ryuko (Parent) November 21 2016

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Questions Hayden has answered

How do I simplify a surd?

To simplify a surd, remember that sqrt(a*b) = sqrt(a)*sqrt(b) If either a or b are square numbers, you can simply write its square root. Hence, to simplify a surd, you must look for any factors of the number inside the square root that are sqaure numbers. For example,  sqrt(20) = sqrt(4*5) ...

To simplify a surd, remember that

sqrt(a*b) = sqrt(a)*sqrt(b)

If either a or b are square numbers, you can simply write its square root. Hence, to simplify a surd, you must look for any factors of the number inside the square root that are sqaure numbers.

For example, 

sqrt(20) = sqrt(4*5) = sqrt(4)*sqrt(5)

sqrt(4) = 2 therefore sqrt(20) = 2sqrt(5)

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1 year ago

308 views

How do I solve a simultaneous equation with more unknowns than equations?

If a set of equations has more unknowns than equations, you cannot get a value for each unknown. However, you can find the relationships between the variables. Start by rearranging one variable in terms of the others and then plug that equation into the others, eliminating one variable. You wi...

If a set of equations has more unknowns than equations, you cannot get a value for each unknown. However, you can find the relationships between the variables.

Start by rearranging one variable in terms of the others and then plug that equation into the others, eliminating one variable. You will then be able to link the rest of the variables together in terms of each other.

Finally, set one variable as a parameter, say u, and give the values of all the variable in terms of that uniting parameter.

For example, you will end up with something like:

x = 2u - 1

y = 1/2u + 4

z = u

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1 year ago

298 views

What if my equation doesn't factorise?

For all quadratic equations, you can use the quadratic formula. Given an equation of the form ax2+bx+c, you can plug those values into this formula: x1, x2 = (-b +/- sqrt(b2 - 4ac)) / 2a Note: the term b2 - 4ac is called the determinant  and must be greater than 0 for your equation to have an...

For all quadratic equations, you can use the quadratic formula. Given an equation of the form ax2+bx+c, you can plug those values into this formula:

x1, x= (-b +/- sqrt(b- 4ac)) / 2a

Note: the term b- 4ac is called the determinant  and must be greater than 0 for your equation to have any solutions.

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1 year ago

300 views
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