Hayden M. A Level Further Mathematics  tutor, GCSE Maths tutor, A Lev...

Hayden M.

£30 /hr

Currently unavailable: for new students

Studying: Physics (Masters) - Warwick University

5.0
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21 reviews| 22 completed tutorials

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About me

Hi, my name is Hayden. I am a high-performing 3rd year Physics student at The University of Warwick. I get excited about all things science and I hope that I can help you not only learn your material but also understand why it is a useful thing to know. As a person, I am very relaxed. Hence, if you tend to get stressed out when you don't understand something, I'm sure we can balance each other out and figure out a way to make it 'click'. As for what you want to be taught: that's up to you. Exam questions, lesson-like explanations of theory, helping you work through some homework - you decide and I'll do my best to help. Still not convinced? Book a free 'meet the tutor' session with me to get a feel for my personality and teaching style. I look forward to meeting with you, thanks.Hi, my name is Hayden. I am a high-performing 3rd year Physics student at The University of Warwick. I get excited about all things science and I hope that I can help you not only learn your material but also understand why it is a useful thing to know. As a person, I am very relaxed. Hence, if you tend to get stressed out when you don't understand something, I'm sure we can balance each other out and figure out a way to make it 'click'. As for what you want to be taught: that's up to you. Exam questions, lesson-like explanations of theory, helping you work through some homework - you decide and I'll do my best to help. Still not convinced? Book a free 'meet the tutor' session with me to get a feel for my personality and teaching style. I look forward to meeting with you, thanks.

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Ratings & Reviews

5from 21 customer reviews
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Ryuko (Parent)

October 1 2016

Very good first session. It was clear and easy to follow. Thank you.

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Ryuko (Parent)

March 15 2017

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Ryuko (Parent)

March 8 2017

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Ryuko (Parent)

February 16 2017

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
PhysicsA-level (A2)A*
ChemistryA-level (A2)A
Further MathematicsA-level (A2)A

General Availability

Before 12pm12pm - 5pmAfter 5pm
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sundays

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£30 /hr
MathsA Level£30 /hr
PhysicsA Level£30 /hr
ChemistryGCSE£30 /hr
EnglishGCSE£30 /hr
MathsGCSE£30 /hr
PhysicsGCSE£30 /hr
ScienceGCSE£30 /hr

Questions Hayden has answered

How do I simplify a surd?

To simplify a surd, remember that

sqrt(a*b) = sqrt(a)*sqrt(b)

If either a or b are square numbers, you can simply write its square root. Hence, to simplify a surd, you must look for any factors of the number inside the square root that are sqaure numbers.

For example, 

sqrt(20) = sqrt(4*5) = sqrt(4)*sqrt(5)

sqrt(4) = 2 therefore sqrt(20) = 2sqrt(5)

To simplify a surd, remember that

sqrt(a*b) = sqrt(a)*sqrt(b)

If either a or b are square numbers, you can simply write its square root. Hence, to simplify a surd, you must look for any factors of the number inside the square root that are sqaure numbers.

For example, 

sqrt(20) = sqrt(4*5) = sqrt(4)*sqrt(5)

sqrt(4) = 2 therefore sqrt(20) = 2sqrt(5)

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2 years ago

1206 views

How do I solve a simultaneous equation with more unknowns than equations?

If a set of equations has more unknowns than equations, you cannot get a value for each unknown. However, you can find the relationships between the variables.

Start by rearranging one variable in terms of the others and then plug that equation into the others, eliminating one variable. You will then be able to link the rest of the variables together in terms of each other.

Finally, set one variable as a parameter, say u, and give the values of all the variable in terms of that uniting parameter.

For example, you will end up with something like:

x = 2u - 1

y = 1/2u + 4

z = u

If a set of equations has more unknowns than equations, you cannot get a value for each unknown. However, you can find the relationships between the variables.

Start by rearranging one variable in terms of the others and then plug that equation into the others, eliminating one variable. You will then be able to link the rest of the variables together in terms of each other.

Finally, set one variable as a parameter, say u, and give the values of all the variable in terms of that uniting parameter.

For example, you will end up with something like:

x = 2u - 1

y = 1/2u + 4

z = u

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2 years ago

798 views

What if my equation doesn't factorise?

For all quadratic equations, you can use the quadratic formula. Given an equation of the form ax2+bx+c, you can plug those values into this formula:

x1, x= (-b +/- sqrt(b- 4ac)) / 2a

Note: the term b- 4ac is called the determinant  and must be greater than 0 for your equation to have any solutions.

For all quadratic equations, you can use the quadratic formula. Given an equation of the form ax2+bx+c, you can plug those values into this formula:

x1, x= (-b +/- sqrt(b- 4ac)) / 2a

Note: the term b- 4ac is called the determinant  and must be greater than 0 for your equation to have any solutions.

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2 years ago

810 views

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