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Ian R.

Currently unavailable: until 01/09/2016

Degree: MSc International Development (Masters) - Edinburgh University

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About me

My name is Ian and I am an experienced tutor specialising in Maths, Physics and English as Foreign language. I am currently a Masters student at the University of Edinburgh studying International Development My previous studies include a BA and an MSc in Experimental and Theoretical Physics at the University of Cambridge as well as a scholarship year in Fukuoka, Japan where I studied Japanese.

For the past two years I have been working for a charity as a manager of one of their learning centres which provide academic support sessions and deliver customised education programmes for schools and students aged 7-19. As part of the charity's leadership team I also trained staff on how to best provide tuition to students and took specific responsibility for the implementation of the charity's university application support as well as schemes run with the universities of Cambridge and Oxford.

Prior to this I worked as an English as a Foreign Language (EFL) teacher in both the UK and Japan. As well as providing tailored tuition in a broad range of subjects, I have designed and delivered a variety of educational programmes in conjunction with schools and teachers. This has given me a clear understanding of educational frameworks and assessment criteria and how to support students to achieve their academic targets..

Due to my previous work supporting students with university applications and with CVs, I am also capable of delivering sessions themed around personal statements and job applications.

I am passionate about supporting young people to achieve their academic potential. In order to do this I work with tutees to understand their individual learning needs and their particular goals and to then formulate a step-by-step plan which will allow them to achieve their targets.. The first session I provide will be based on this and so will often involve an exploration of current knowledge as well as opportunities to build rapport and trust with the tutee which is vitally important for a successful tutoring experience.

At the heart of my tutoring is a calm and patient approach which creates an environment conducive to learning and encourages the student to explore their own ideas and to apply their knowledge to tackle new and unfamiliar questions and concepts.

Subjects offered

SubjectLevelMy prices
Maths A Level £26 /hr
Maths GCSE £24 /hr
Physics GCSE £24 /hr
Science GCSE £24 /hr
Physics IB £26 /hr

Qualifications

QualificationLevelGrade
Natural Sciences: PhysicsMasters Degree2.1
Natural Sciences: PhysicsBachelors Degree2.1
PhysicsAdvanced HigherA
MathematicsAdvanced HigherA
Applied MathematicsAdvanced HigherA
Religious, Moral and Philosophical StudiesAdvanced HigherA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: until

01/09/2016

Questions Ian has answered

Simplify (7+sqrt(5))/(sqrt(5)-1), leaving the answer in the form a+b*sqrt(5)

Step 1 - Identify the difference between the required form of the answer and the expression to be simplified:  It can be seen that in order to simplify the expression we need to somehow get rid of the denominator. Step 2 - Attempt a method to get rid of the denominator:  The best way to get ...

Step 1 - Identify the difference between the required form of the answer and the expression to be simplified: 

It can be seen that in order to simplify the expression we need to somehow get rid of the denominator.

Step 2 - Attempt a method to get rid of the denominator: 

The best way to get rid of the denominator is to multiply it by (sqrt(5)+1). In order to keep the expression the same we must do the same to the numerator as well. 

This gives us,

((7+sqrt(5))/(sqrt(5)-1))*((sqrt(5)+1)/(sqrt(5)+1))

Step 3 - Carry out the necessary calculations:

The top parts of the fractions multiply together and the bottom parts of the fractions multiply together.

For the top part this gives us,

(7+sqrt(5))*(sqrt(5)+1) = 7*sqrt(5)+7+5+sqrt(5)

= 8*sqrt(5)+12

For the bottom part this gives us,

(sqrt(5)-1)*(sqrt(5)+1) = 5+sqrt(5)-sqrt(5)-1 = 4

Dividing the top part by the bottom part gives us,

2*sqrt(5)+3

Step 4 - Check that the answer is in the correct form.

The question asks for an answer in the form,

a+b*sqrt(5)

Our answer can be written in this format with a = 3 and b = 2.

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1 year ago

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