James B. A Level Maths tutor, GCSE Maths tutor

James B.

£24 - £26 /hr

Currently unavailable: for regular students

Studying: Mathematics (Masters) - Exeter University

5.0
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58 reviews| 133 completed tutorials

Contact James

About me

About Me I'm a third year student at Exeter University. I've been passionate about maths from a young age and have carried that love through my school and uni career. I hope that I can generate the same passion for my tutees as well. I also hold a qualification in TEFL, and can tutor to improve your English at any level, don't hesitate to ask! I'm a patient and friendly person, and have always enjoyed helping friends and family with their work. I enjoy teaching people about my subject and I will always bring enthusiasm to our sessions. The Sessions You guide the topics that we will cover in our sessions. I'll make sure you understand the basics before we tackle the harder topics, once you have basic understanding of a topic, the rest falls into place. I will do my best to find out what style of learner you are so that I can tailor each tutorial to you, such as including more examples, more diagrams or by finding new ways of explaining ideas. I will not simply talk at you, I will be engaging and make sure that any question you have is answered. What Next? If you have any questions, don't hesitate, send me a "WebMail" or organise a Free Trial Session, I look forward to meeting you!

About Me I'm a third year student at Exeter University. I've been passionate about maths from a young age and have carried that love through my school and uni career. I hope that I can generate the same passion for my tutees as well. I also hold a qualification in TEFL, and can tutor to improve your English at any level, don't hesitate to ask! I'm a patient and friendly person, and have always enjoyed helping friends and family with their work. I enjoy teaching people about my subject and I will always bring enthusiasm to our sessions. The Sessions You guide the topics that we will cover in our sessions. I'll make sure you understand the basics before we tackle the harder topics, once you have basic understanding of a topic, the rest falls into place. I will do my best to find out what style of learner you are so that I can tailor each tutorial to you, such as including more examples, more diagrams or by finding new ways of explaining ideas. I will not simply talk at you, I will be engaging and make sure that any question you have is answered. What Next? If you have any questions, don't hesitate, send me a "WebMail" or organise a Free Trial Session, I look forward to meeting you!

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About my sessions

My Maths lesson subjects are chosen by you if you have particular areas to focus on, or me if you want a general rounded set of lessons. I will focus mainly on example driven work, coaching you through examples and teaching around those areas to improve your understanding.

My English lessons are pre prepared and follow lesson plans written by me for classes that I teach but tailored towards one on one tuition, if there is an area of the language you would like to focus on however that can be arranged too. I do not teach for a particular syllabus but to improve your day to day language skills.

My Maths lesson subjects are chosen by you if you have particular areas to focus on, or me if you want a general rounded set of lessons. I will focus mainly on example driven work, coaching you through examples and teaching around those areas to improve your understanding.

My English lessons are pre prepared and follow lesson plans written by me for classes that I teach but tailored towards one on one tuition, if there is an area of the language you would like to focus on however that can be arranged too. I do not teach for a particular syllabus but to improve your day to day language skills.

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Ratings & Reviews

5from 58 customer reviews
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Emma (Parent)

March 8 2017

Reliable, conscientious and patient tutor.

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Thomas (Student)

March 8 2017

Another constructive lesson, thank you

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Emma (Parent)

February 26 2017

James always manages to get across how to approach questions and is supportive in his teaching. Always fell positive after a session.

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Judith (Parent)

December 21 2016

good

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
Further MathsA-level (A2)A
ChemistryA-level (A2)A

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£26 /hr
MathsGCSE£24 /hr

Questions James has answered

How do you differentiate X to the power of a?

To differentiate Xa, where a is any real number, you multiply X by a, and subtract 1 from the power.

i.e. d(Xa)/dX=aXa-1

To differentiate Xa, where a is any real number, you multiply X by a, and subtract 1 from the power.

i.e. d(Xa)/dX=aXa-1

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2 years ago

800 views

How to prove that (from i=0 to n)Σi^2= (n/6)(n+1)(2n+1), by induction.

First you must show that the statement on the right hand side is true for n=1:

Σi=0 iwhen n=1, is equal to 12=1

(1/6)(1+1)(1+2)=(1/6)(2)(3)=1

This means that the statement is true for n=1.

Next you assume that it is true for 'k', where k is any number, and so you get;

Σi=0 i2 when n=k, is equal to (k/6)(k+1)(2k+2)

You then have to show that the statement is true for n=k+1 which would make;

Σi=0 i2 when n=k+1, is equal to (k+1)/6(k+2)(2k+3) call this 1)

As the left hand side is a sum, it can be written as;

Σi=0 i2 when n=k + (k+1)2

We already know the sum of i2 when n=k and so we can substitute it in;

(k/6)(k+1)(2k+1) + (k+1)2

We then try and reach 1)

We can factorise out (k+1)

(k+1)[(k/6)(2k+1) +k+1]

Next, multiply the inner brackets;

(k+1)[2k2/6+k/6 +k+1]

Take out a factor of 1/6

(k+1)/6(2k2+k+6k+6)= (k+1)/6(2k2+7k+6)

Finally, factorise the inner bracket;

(k+1)/6(k+2)(2k+3)

As this is equal to 1), we have proven that the statement is true for all values of n.

First you must show that the statement on the right hand side is true for n=1:

Σi=0 iwhen n=1, is equal to 12=1

(1/6)(1+1)(1+2)=(1/6)(2)(3)=1

This means that the statement is true for n=1.

Next you assume that it is true for 'k', where k is any number, and so you get;

Σi=0 i2 when n=k, is equal to (k/6)(k+1)(2k+2)

You then have to show that the statement is true for n=k+1 which would make;

Σi=0 i2 when n=k+1, is equal to (k+1)/6(k+2)(2k+3) call this 1)

As the left hand side is a sum, it can be written as;

Σi=0 i2 when n=k + (k+1)2

We already know the sum of i2 when n=k and so we can substitute it in;

(k/6)(k+1)(2k+1) + (k+1)2

We then try and reach 1)

We can factorise out (k+1)

(k+1)[(k/6)(2k+1) +k+1]

Next, multiply the inner brackets;

(k+1)[2k2/6+k/6 +k+1]

Take out a factor of 1/6

(k+1)/6(2k2+k+6k+6)= (k+1)/6(2k2+7k+6)

Finally, factorise the inner bracket;

(k+1)/6(k+2)(2k+3)

As this is equal to 1), we have proven that the statement is true for all values of n.

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2 years ago

1671 views

What is "Standard Form"?

Standard form is a way of writing large numbers to make them more compact, for example

Instead of writing:

197,000,000

We say:

197,000,000= 1.97 x 100,000,000

And so we can write:

1.97 x 108, which is more concise.

Standard form is a way of writing large numbers to make them more compact, for example

Instead of writing:

197,000,000

We say:

197,000,000= 1.97 x 100,000,000

And so we can write:

1.97 x 108, which is more concise.

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2 years ago

905 views

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