Meabh M. GCSE Maths tutor, GCSE English tutor, GCSE History tutor
£20 /hr

Meabh M.

Degree: Law (Bachelors) - Durham University

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About me

A little bit about me: I am a Law student at Durham University. I have always enjoyed Maths, History and English Literature (even if it is an odd mix) and I can only hope that this will come through in my tutorials. I am very friendly and approachable and I have had experience in teaching through leading Speech and Drama lessons. Before coming to University I helped younger students who were struggling in subjects like Maths and English Literature and tutored them through a ‘buddy system’ in my school. What can you expect in tutorials? In tutorials you will decide what you want to cover and you can pick topics that are just not sitting right with you. In Maths we can find ways and methods that will help you fully understand what you are doing. We will use different ways to help you understand (short clips of videos, diagrams, past paper questions) until you are confident that you will be able to answer any question on that topic. If you need help with how to structure an essay, or understanding content in English and History we can find fun and enjoyable ways to make sure you never forget the vital information. Anything you feel uncomfortable about can be covered in our 55 minute tutorials and hopefully by the end of the session you will feel confident and comfortable in your ability.  You can contact me through booking ‘Meet a Tutor Session.’ I look forward to meeting you and I am happy to help in any way!

Subjects offered

SubjectQualificationPrices
English GCSE £20 /hr
History GCSE £20 /hr
Maths GCSE £20 /hr

Qualifications

SubjectQualificationLevelGrade
English LiteratureA-levelA2A
MathsA-levelA2A
Theatre StudiesA-levelA2A
HistoryA-levelA2A*
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Ratings and reviews

4.5from 23 customer reviews

Stacey (Parent) June 12 2017

I've noticed a massive change in my daughters whole approach to her exams thanks to Maebh. She has been an extremely positive influence. It has been a delight to see my daughter grow in confidence with each lesson. Thank you Maebh.

Stacey (Parent) May 24 2017

Maebh is very good at helping cover the points that are needed. My child's confidence has rocketed with Maebh's help

Stacey (Parent) May 16 2017

Kallista did well on Simultaneous equations. She seems more confident with each lesson. Thank you

Stacey (Parent) May 10 2017

Kallista is improving and her confidence seems to be lifting greatly
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Questions Meabh has answered

How can I solve simultaneous equations?

We can solve simultaneous equations in two different ways. We can either eliminate one of the unknowns or use substitution. It is about finding which method you are most comfortable with and practicing that method. We will first look at the method of elimination. If I am given the two equatio...

We can solve simultaneous equations in two different ways. We can either eliminate one of the unknowns or use substitution. It is about finding which method you are most comfortable with and practicing that method. We will first look at the method of elimination.

If I am given the two equations:

2x + y = 7

3x - y = 8 

To begin I would add the two equations to get rid of the y. So 

2x + y = 7

+

3x - y = 8

would become: 5x = 15

(if the equations had two positive y's we would then subtract the equations to get rid of the y.)

With the 5x = 15 we can get what value x would have by dividing 15 by 5.

Then x = 3.

Since we know that x = 3 all we have to do is put 3 back into one of the original equations to find out what y is. 

so 2x + y = 7 would become (2x3) + y =7 which is 6+y= 7

y=7-6 so y=1.

The answers are then x=3 and y=1. 

We will now look at the method of substitution.

If we are given the equations of:

y - 2x = 1

2y -3x = 5

We can rearrange y - 2x =1 to become 

y=1+2x

We can then substitute y into the other equation so 

2(1+2x) - 3x = 5

2 + 4x -3x = 5

2 + x = 5

x= 5-2

x=3 

Now that we know what x is we can substitute it into one of equations to find out what y is

so y-2x=1

y- (2x3) =1

y-6=1

y= 1+6

y=7

So the answer is x=3 and y=7

SImultaneous equations can look difficult but after some practice and finding out what method you prefer you will be able to solve them!

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2 years ago

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