Why choose me for your personal guide into the science? Well, I have been studying math and physics very intensively in high school and I was prepared by the best teachers in my country. Competitions have become an integral part of my life and they have greatly contributed to my love for problem solving. Having competed for nine years, I know that there is no easy way to achieve a goal set. Because of that, my main work will be to make everyone understand even the smaller parts of the problem. You will be the one who will guide us and who will determine which part of the material you want from us to cover.
Exams? Don't worry! There is nothing bad about exams but everyone is nervous when they come. The good plan is one of the most important parts of the preparation. I will be happy to help you create it. Then we will need to practise a lot and to follow the plan. And just before the exam, you will be calm and this would be not by surprise.
I am now a student at the University of Edinburgh and I just passed my first university exams. I undestand that it is really hard to study alone and that's the reason why I want to help others. This way the studying and revising would be a really good fun! I promise! :)
If you have some question, just send me a message. I would be glad to answer you! And please tell me in advance your exam board and the topic of the material you want us to cover.
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Ope (Parent) September 25 2016
Our first step in this physics problem should be to identify all of the forces that act on the objects. There are two forces here,electrical and gravitational. Since both objects have the same charge in magnitude(like charges), the electrical force should be repulsive and equal to F(el) = (k*q^2)/ r^2.
The gravitational force, on the other hand, is always attractive and equal to F(gr) = (G*m^2)/r^2. In orde the objects to be balanced, F(el) = F(gr). Therefore,
(k*q^2)/ r^2 = (G*m^2)/r^2
m = (square roof of (k/G) ) * q kg.see more
This exercise is asking to prove the existance of the square root of 2. So let's consider the function f(x) = x^2. Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity). Using the Intermidiate Value Theorem, it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3. Therefore,
f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3] and taking N=2, we can therefore guarantee the existance of a number c such that 0