Eliza G.

Eliza G.

£18 - £25 /hr

Economics and Politics (Bachelors) - Edinburgh University

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About me

Hi, My name is Eliza. I am 19 years old and currently in my first year at Edinburgh University studying Economic and Politics. I received 3 As as A Level in English, Maths and Economics.

Maths is an extremely large part of my degree meaning my knowledge and enjoyment of the subject is constantly being refreshed. I am extremely passionate about the subject, finding it both challenging and satisfying when concepts are finally understood. I therefore believe I am well suited to help tutor maths at both GCSE and A level as with my knowledge constantly growing through my degree studies I can also help my tutees understand concepts new to them.

Hi, My name is Eliza. I am 19 years old and currently in my first year at Edinburgh University studying Economic and Politics. I received 3 As as A Level in English, Maths and Economics.

Maths is an extremely large part of my degree meaning my knowledge and enjoyment of the subject is constantly being refreshed. I am extremely passionate about the subject, finding it both challenging and satisfying when concepts are finally understood. I therefore believe I am well suited to help tutor maths at both GCSE and A level as with my knowledge constantly growing through my degree studies I can also help my tutees understand concepts new to them.

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About my sessions

I believe the best way to learn is to be asked questions, meaning students are constantly being pushed to fully understand and grasp concepts. I will go through mathematical concepts step by step explaining not only what should be done but also also why it has to be done as I feel this ensures a deep understanding helping students learn how to apply different strategies to set questions. I will work through specified topics each session, starting with an explanation and examples then ask the student to complete a series of questions to solidify their understanding.

I believe the best way to learn is to be asked questions, meaning students are constantly being pushed to fully understand and grasp concepts. I will go through mathematical concepts step by step explaining not only what should be done but also also why it has to be done as I feel this ensures a deep understanding helping students learn how to apply different strategies to set questions. I will work through specified topics each session, starting with an explanation and examples then ask the student to complete a series of questions to solidify their understanding.

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Qualifications

SubjectQualificationGrade
English LiteratureA-level (A2)A
EconomicsA-level (A2)A
MathsA-level (A2)A

General Availability

MonTueWedThuFriSatSun
Pre 12pm
12 - 5pm
After 5pm

Pre 12pm

12 - 5pm

After 5pm
Mon
Tue
Wed
Thu
Fri
Sat
Sun

Subjects offered

SubjectQualificationPrices
EnglishGCSE£18 /hr
MathsGCSE£18 /hr
UCATUniversity£25 /hr

Questions Eliza has answered

Point P lies on the curve y=2x^3 + 3x^2 + 2. The gradient of the curve at P is -3/2. Find the coordinates of point P.

Firstly I would explain that differentiation should be used as the derivative of a curve shows the gradient. I would then ask the student to differentiate the curve remembering that the general formula for differentiation is nxn-1. Therefore the derivative would be 6x2 + 6x. The 2 disappears as the derivative of an integer is 0, as the value of an integer does not change with respect to x. As we know the gradient of the curve at point P we will need to equate it to the formula for the gradient we just calculated, giving us 6x2 + 6x = -3/2. This could be rearranged to give 6x2 + 6x + 3/2 = 0 By recognising that we now have a quadratic to solve I would ask the student to use the quadratic formula, this would give us an answer of x= -0.5Finally to find the final coordinate (the y coordinate) I would ask the student to sub x= -0..5 into the equation for the curve, which would give the final coordinates of P as (-0.5, 2.5)Firstly I would explain that differentiation should be used as the derivative of a curve shows the gradient. I would then ask the student to differentiate the curve remembering that the general formula for differentiation is nxn-1. Therefore the derivative would be 6x2 + 6x. The 2 disappears as the derivative of an integer is 0, as the value of an integer does not change with respect to x. As we know the gradient of the curve at point P we will need to equate it to the formula for the gradient we just calculated, giving us 6x2 + 6x = -3/2. This could be rearranged to give 6x2 + 6x + 3/2 = 0 By recognising that we now have a quadratic to solve I would ask the student to use the quadratic formula, this would give us an answer of x= -0.5Finally to find the final coordinate (the y coordinate) I would ask the student to sub x= -0..5 into the equation for the curve, which would give the final coordinates of P as (-0.5, 2.5)

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1 month ago

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