PremiumJenny B.

Jenny B.

£30 /hr

Currently unavailable: for regular students

Studying: Chemistry (Doctorate) - Sheffield University

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About me

Who am I?

I've just finished my PhD in Chemistry at the University of Sheffield. I now "do science" for a job and I love it! I'm now looking to pass on my knowledge and enthusiasm on to the next generation of "scientists".

I haven't always been able to do science, and have struggled in the past myself needing help with understanding some of the more complicated theories in the GCSE and A-level science syllabuses. I have a lot of experience both as a tutee and a tutor (teaching in university labs and tutorials). I like to think I'm very friendly, approachable and very to happy to help!!!

How can I help?

Having had tutors in the past I know what works and what doesn't!

I'd like my sessions to be led by you, so that you're getting the most out of it. So we can focus particular areas you might be struggling with or just brush up on the subject as a whole.

I like pictures and diagrams so I'm a very visual tutor (I think this help with really understanding the basic science)! Once we've grasped the basics, we can move on to brushing up on that good old exam practice!! ;)

Who am I?

I've just finished my PhD in Chemistry at the University of Sheffield. I now "do science" for a job and I love it! I'm now looking to pass on my knowledge and enthusiasm on to the next generation of "scientists".

I haven't always been able to do science, and have struggled in the past myself needing help with understanding some of the more complicated theories in the GCSE and A-level science syllabuses. I have a lot of experience both as a tutee and a tutor (teaching in university labs and tutorials). I like to think I'm very friendly, approachable and very to happy to help!!!

How can I help?

Having had tutors in the past I know what works and what doesn't!

I'd like my sessions to be led by you, so that you're getting the most out of it. So we can focus particular areas you might be struggling with or just brush up on the subject as a whole.

I like pictures and diagrams so I'm a very visual tutor (I think this help with really understanding the basic science)! Once we've grasped the basics, we can move on to brushing up on that good old exam practice!! ;)

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Qualifications

SubjectQualificationGrade
ChemistryDegree (Bachelors)1st
ChemistryDoctorateN/A

General Availability

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Subjects offered

SubjectQualificationPrices
ChemistryA Level£30 /hr
BiologyGCSE£30 /hr
ChemistryGCSE£30 /hr
MathsGCSE£30 /hr
PhysicsGCSE£30 /hr

Questions Jenny has answered

How do I calculate the relative formula mass of Calcium carbonate (CaCO3)

The relative formula madd of a compound comes from the total mass of all of the elments within the compound.

So in the case of calcium carbonate (CaCO3) we have;

                              1 x Ca

                               1 x C

                               3 x O

So we first need to know the relative mass nnumber (Mr) of these individual elements. This information comes from the periodic table and is determined by the number of protons + neutrons in an atom.

            Mass number = protons + neutrons

So if we look at the elements in our compound we have;

                                     20Ca40  6C12  8O16

In each case the mass number is the bottom right number (in bold), we can now calculate our relative formula mass using these numbers so we have;

           Ca(1 x 40) + C(1 x 12) + O(3 x 16)

    =     40 + 12 + 48

   =       100 g/mol

The units of relative formula mass are g/mol, which tells us that 1 mole of CaCO3 has a mass of 100 g.

The relative formula madd of a compound comes from the total mass of all of the elments within the compound.

So in the case of calcium carbonate (CaCO3) we have;

                              1 x Ca

                               1 x C

                               3 x O

So we first need to know the relative mass nnumber (Mr) of these individual elements. This information comes from the periodic table and is determined by the number of protons + neutrons in an atom.

            Mass number = protons + neutrons

So if we look at the elements in our compound we have;

                                     20Ca40  6C12  8O16

In each case the mass number is the bottom right number (in bold), we can now calculate our relative formula mass using these numbers so we have;

           Ca(1 x 40) + C(1 x 12) + O(3 x 16)

    =     40 + 12 + 48

   =       100 g/mol

The units of relative formula mass are g/mol, which tells us that 1 mole of CaCO3 has a mass of 100 g.

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2 years ago

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