Robin B. GCSE Maths tutor, GCSE Biology tutor, A Level Biology tutor,...

Robin B.

Currently unavailable: for new students

Degree: Medicine (Bachelors) - Oxford, Merton College University

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About me

About me 

Hello! My name is Robin and I'm a 3rd year Medical Student at Oxford University. I have loads of experience working with, supporting and motivating young people of different ages. This includes being a volunteer assistant coach at a running club, carrying out educational research with primary school children, supporting younger pupils at school with guided reading, and just generally being the go-to-guy when you were struggling with your maths homework at school! I also have a strong academic background, for example scoring full marks in A Level Maths. 

What will my tutoring be like? 

I believe that tutoring should be both focused and enjoyable. Let me know which topics you are struggling with, and how you think you learn best, and I will mould the tutorials so that you can get the maximum possible benefit from them. I will help you really understand topics so that you can tackle anything the exam paper might throw at you. I also believe exam technique is pivotal to scoring what you deserve, so I'll cover this, particular strategies to check for errors so you can mop up every mark you possibly can! Most of all I want you to enjoy the tutorials, because I want you to come out of them loving maths and science as much as I do! 

What do I expect from you? 
Just come enthusiastic and willing to learn! 

How can I find out more/find out if you are right for me? 
Why not send me a message, or go ahead and book a 'Meet The Tutor' session? I can't wait to hear from you!

Subjects offered

SubjectLevelMy prices
Biology A Level £20 /hr
Biology GCSE £18 /hr
Chemistry GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
Science GCSE £18 /hr
-Medical School Preparation- Mentoring £20 /hr
-Oxbridge Preparation- Mentoring £20 /hr
.BMAT (BioMedical Admissions) Uni Admissions Test £25 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further Mathematics A-LevelA*
ChemistryA-LevelA*
BiologyA-LevelA
BMATUni Admissions Test7.5, 5.8, 4.5A
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

25/10/2014

Currently unavailable: for new students

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

5from 4 customer reviews

Austin (Student) October 29 2016

Very prepared for lessons and has helped to polish up my essay writing skills.

Sarah (Student) October 27 2016

Really a remarkable tutor. Super prepared for lessons, explains everything extremely clearly and step by step. Have had many tutors in the past but he's definitely one of the best.

Austin (Student) October 26 2016

Explanations were very good and taught me how to structure more detailed arguments.

Sarah (Student) October 25 2016

Extremely good at explaining concepts and helping one apply them. Made everything much simpler and easier to understans

Questions Robin has answered

The first three terms of a sequence are a, b, c. The term-to-term rule of the sequence is 'Multiply by 2 and subtract 4'. Show that c = 4(a – 3).

As the answer is given in the question, it's really important that you lay out your working carefully to give a convincing account as to how you got from the question to the answer.  Here we have a sequence. This means that there is a fixed rule that determines how you get from one number to ...

As the answer is given in the question, it's really important that you lay out your working carefully to give a convincing account as to how you got from the question to the answer. 

Here we have a sequence. This means that there is a fixed rule that determines how you get from one number to the next... or here, from one letter to the next, because the question is using an algebraic progression.  

The first letter in our sequence is a. To get to b we must multiply by 2 and subtract 4. a multiplied by 2 is 2a, and then subtracting 4 gives 2a - 4. Therefore, b = 2a-4. 

To get to the third letter in our sequence, c, we must take b and again multiply by 2 and subtract 4. As b = 2a-4, we must multiply this by 2, giving 2(2a-4) and then subtract 4, giving 2(2a-4) - 4. It is very important here to consider the brackets. Remember that we are doubling b, and so we must double the entire expression that we now have for b, and so we put brackets around it. 

So now we have c = 2(2a-4) - 4. This isn't quite the expression that we are working towards, but we can get there by expanding and then re-factorising. To expand the bracket, we multiply everything inside it by 2. This gives 4a - 8. Subtracting the other 4 gives c = 4a - 12. We can now go straight to the answer in the question, because both terms of the expression (4a and -12) are divisible by 4, giving c = 4((4a/4) - (12/4)) = 4(a-3). 
 

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2 months ago

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