Currently unavailable: for regular students
Degree: Engineering (Bachelors) - Exeter University
I'm in my first year at the University of Exeter studying Mechanical Engineering. My favourite subjects are Maths & Science and my physics teacher is who inspired me to really love teaching others. He was great at using analogies to explain even the most complicated topics and his passion was really infectious! I have a younger brother and a lot of expirience helping him & his friends through tricky probelms - I find it really rewarding seeing that moment when it clicks and it just makes sense and would love to help you find the same.
My Tutoring sessions:
I understand everyone learns in different ways so will be happy to let you lead and tell me what works best for you. I also believe that questions/example problems are some of the best ways to practice for exams and find what you still dont understand so feel free to have some ready for me to work through with you.
When I applied to University my school really pushed us to perfect our personal statements and I learnt a lot of hints/tips which lead me to recieveing all 5 offers from the universities I chose to apply to. I'd love to help you through the process to make sure you pesent the best version of yourself to Universities.
How to contact me:
Use the form on this webpage to send me any questions or book a meeting/tutorial with me - I'd love to hear from you!
|Design & Technology||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|Design & Technology||GCSE||£18 /hr|
|Maths||13 Plus||£18 /hr|
|Maths||11 Plus||£18 /hr|
|-Personal Statements-||Mentoring||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Anja (Student) April 20 2016
Joshua (Student) April 11 2016
This is an A* level GCSE Maths question. 'Solve' means we need to find what value x represents, but in the question this x appears on the denominator (bottom half) of the fractions which we can't use. So the first thing we have to do is multiply out by the denominators to get rid of them. Lets do this one by one.
So first if we multiply through every term by (x-4) we'll be left with:
(2x+3) - (2x-8)(x-4)/(2x+1) = 1(x-4)
Now lets multiply through every term by (2x+1) which will eliminate the remaining fraction:
(2x+3)(2x+1) - (2x-8)(x-4) = 1(x-4)(2x+1)
Now expand out the brackets (be careful theres going to be a lot of terms) but you should get:
(4x^2+2x+6x+3) - (2x^2-8x-8x+32) = (2x^2-8x-4)
and now simplify \9being careful with the negatives) to:
2x^2+24x-29 = 2x^2-7x-4
subtract the 2x^2 from both sides, and collect like terms (so all x's on one side of the equation, and numbers on the other) do this by moving the 7x to the left hand side (+7x to both sides) and 29 to the right hand side (+29 to both sides) this will give you:
divide both sides by 31:
But remember the question asked for the answer to be given to 2 decimal places so:
x=0.81 (2 d.p.)see more