Currently unavailable: for new students

Degree: Medicinal and Biological Chemistry (Masters) - Edinburgh University

Hello I'm Lily and I'm a second year Chemist at the University of Edinburgh. Being passionate and enthusiastic about my subject means that I'm eager to help students conquer their difficulties with Chemistry to not only achieve the grades they desire but also enjoy learning the subject

I'm avaliable for regular tutorials or just a one off to help with a particular area you're struggling with.

The session:

Sessions will be relaxed but productive, and will focus on helping you overcome any difficulties. Whilst studying for my A-levels/GCSEs I found past papers an effective way of achieving top grades and will try to incorporate these into our sessions. However I'm flexible in my teaching and will work to find the best method of learning to suit you.

Contact:

If you have any questions feel free to book a 'Meet the Tutor session' or send me a 'Webmail.' I'm more than happy to help, and I look forward to meeting you.

#### Subjects offered

SubjectQualificationPrices
Chemistry A Level £20 /hr
Chemistry GCSE £18 /hr

#### Qualifications

ChemistryA-levelA2A
MathsA-levelA2A
BiologyA-levelA2A
 CRB/DBS Standard No CRB/DBS Enhanced No

#### Ratings and reviews

5from 6 customer reviews

Peter (Parent) June 11 2016

Thank you for your help :-)

Peter (Parent) February 22 2016

Lily is an excellent teacher.

Peter (Parent) February 18 2016

Lily is a natural teacher - very well organised and supportive.

Peter (Parent) February 8 2016

Thank you for the tutorial
See all reviews

### At what temperature does the reaction become feasible? When ΔH = 492.7 kJmol^-1 and ΔS = 542.6 JK^-1mol^-1.

When a reaction is feasible ΔG = 0. Rearrange the equation ΔG = ΔH - TΔS. So that when ΔG = 0,       T = ΔH / ΔS. Must convert ΔS from JK^-1mol^-1 to kJK^-1mol^-1 by dividing it by 1000. Then plug in numbers given so T = (492.7 kJmol^-1) / (0.5426 kJK^-1mol^-1)  T = 908 K.

When a reaction is feasible ΔG = 0. Rearrange the equation ΔG = ΔH - TΔS. So that when ΔG = 0,       T = ΔH / ΔS.

Must convert ΔS from JK^-1mol^-1 to kJK^-1mol^-1 by dividing it by 1000.

Then plug in numbers given so T = (492.7 kJmol^-1) / (0.5426 kJK^-1mol^-1)

T = 908 K.

see more

2 years ago

1431 views

### Explain why chlorine (Cl2) is a gas at room temperature, but sodium chloride (NaCl) is a solid at room temperature.

The melting/boiling point of a substance determines what state of matter it takes at a certain temperature. In Cl2 there are covalent bonds between the atoms forming simple molecules. There are weak attractions between molecules of Cl2 meaning little energy is needed to break these forces of ...

The melting/boiling point of a substance determines what state of matter it takes at a certain temperature.

In Cl2 there are covalent bonds between the atoms forming simple molecules. There are weak attractions between molecules of Cl2 meaning little energy is needed to break these forces of attraction and therefore Cl2 has a low boiling point.

NaCl on the other hand has strong electrostatic forces of attraction between the positvely charged Na ion and the negatively charged Cl ion. NaCl forms a giant ionic lattice that requires high amounts of energy to break and therefore has a high melting point.

see more

2 years ago

38262 views
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Still comparing tutors?

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this.