Craig  Y. A Level Maths tutor, A Level Physics tutor, GCSE Maths tuto...

Craig Y.

Currently unavailable: for new students

Degree: Theoretical Physics (Masters) - Edinburgh University

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About me

Introductions

Hi! My name is Craig Young and I am a 3rd year student in Theoretical Physics at the University of Edinburgh. 

Science, and especially maths and physics, has been a major passion of mine since I was about 13 years old and since then I have done as much as possible to pursue this passion. There is nothing I enjoy more than encouraging others to share this passion or at least to tolerate it!

Experience

From a young age I've enjoyed helping others to understand something that they previously didn't. This first came about when I began helping to instruct my sister's Tae Kwon Do class and continued through helping to tutor 13-16 year olds in physics and maths during my free periods in my last year of school. I hope I can 

Learning with me

Everything we study is up to YOU. It's your tutorial and therefore everything we cover is dictated by you. Of course, I will have input and suggestions but obviously the person who most understands how you can progress in the fastest and best way possible is you.

I believe that you only fully understand something if you could teach it to someone else, therefore at the start of every session I will prepare a quick ten minutes for you to show me that you have consolidated and understood thoroughly the previous session's content. Ensuring that we don't move on to something else before you're ready!

How else can I help?

Applying for university can be just as intimidating or nerve-wracking as exams so feel free to ask for advice on UCAS applications or entry exams from someone who has been there and done that (and knows that it's really not that scary)!

Steps

If you're still not convinced I'm the best person to helpy you that's okay! MyTutorWeb offers a MeetMyTutor tutorial free of charge where we can chat and see if I'd be the right fit to help you with your education so don't hesitate to request one! 

I hope to hear from you soon!

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Physics A Level £20 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr

Qualifications

QualificationLevelGrade
ChemistryHigherA
English HigherA
MathematicsHigherA
PhysicsHigherA
PsychologyHigherA
ChemistryAdvanced HigherB
MathematicsAdvanced HigherA
PhysicsAdvanced HigherA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for new students

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Ratings and reviews

4.9from 9 customer reviews

Fraser (Student) April 18 2016

some video lag for a wee 10 minutes but nothing much

Ann (Parent) September 26 2016

Ann (Parent) September 21 2016

Ann (Parent) August 8 2016

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Questions Craig has answered

When and how do I use integration by parts?

Integration by parts is used when you would like to find the integral of a composite function made up of two functions of the same variable as which you're integrating with respect to.  The formula for this technique is: (Integral of f(x)g'(x)) = f(x)g(x) - (Integral of f'(x)g(x)) You will n...

Integration by parts is used when you would like to find the integral of a composite function made up of two functions of the same variable as which you're integrating with respect to. 

The formula for this technique is:

(Integral of f(x)g'(x)) = f(x)g(x) - (Integral of f'(x)g(x))

You will notice that we have labelled one of our functions in the expression that we want to integrate as f(x) and one as g'(x). Once we have decided which is which (more on that later) we differentiate f(x) to get f"(x) and integrate g'(x) to get g(x). We then have every component of the above formula and can plug in our values to get the answer.

There are a few things to note, however. The first thing to note is that we can make life much easier for ourselves by deciding carefully which function to label as f(x) and which to label as g'(x).

The thing to keep in mind here is that, if you look at the formula, the solution involves another integration: the integral of f'(x)g(x), so ideally we want this to be a simple integral that can be solved without the need for integration by parts. So, for example, if we have a composite function of xe-2x, it is in our best interest to pick f(x)=x and g'(x)=e-2x, this is because when we differentiate f(x) in this case we are left with f"(x)=1 simplifying our integral of f"(x)g(x) to just the integral of g(x). Note that it is never a good idea to make an exponential of euler's number f(x) because it will never disappear under differentiation.

Sadly it is not always possible to integrate a composite function using only one iteration of integration by parts. For example if we had a composite function of x2e-2x we would be left with the integral of f"(x)g(x) being equal to 2xe-2x which would need to be integrated by parts again. 

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9 months ago

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