|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Giada (Parent) December 16 2016
Giada (Parent) December 13 2016
Giada (Parent) December 12 2016
Giada (Parent) January 28 2017
V=IR, where V is voltage (volts), I is current (amps) and R is resistance (ohms). Since V and R are known, I needs to be found. Rearranging the equation gives: I=V/R. Inputting the values gives I=12/3. I=4A
Use the chain rule: f'(x) = v(du/dx) +u(dv/dx).
Let u = 2x, du/dx = 2, v = lnx, dv/dx = 1/x
Using this information: f'(x) = 2lnx + 2x/x
This simplifies to f'(x) = 2lnx +2.
First factorise the equation into 2 sets of brackets: You can do this by looking at the constant in the quadratic, 8. Try and find 2 numbers that multiply together to make 8 (such as 4 and 2), and that can be added or subtracted to make the coefficient of the middle term, 2. This results in: (x-4)(x+2)=0. To make the equation true, the left side must equal 0. Either bracket can equal 0. For the first let x=4 (as 4-4=0). For the second, x=-2. These are the answers, x=4 and x=-2see more