Tom V. GCSE Maths tutor, A Level Maths tutor, GCSE Physics tutor, A L...
£18 - £20 /hr

Tom V.

Degree: Mechanical Engineering (Masters) - Leeds University

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About me

About Me

Hello! I'm Tom, I'm in my second year studying medical engineering at the University of Leeds. I've always loved sicence, being particularly drawn to physics and maths from a young age. I loved the methodical, logical approach to maths and its staggering relevance to everything from space travel to art (check out the golden ratio in the Mona Lisa). I've had experience tutoring in maths and chemistry previously, helping GCSE students to boost their grades in the run up to exams. 

The Sessions

I know it can be really daunting thinking about that dreaded maths exam! Nevertheless, I'm here to assure you that there's nothing to fear, and that maths and physics can actually be enjoyable (shhh don't tell anyone). 

During the tutorials, we will discuss any areas you're struggling with, then proceed to tackle topics like so:

1) I explain the general rules and principles surrounding the topic

2) I'll walk you through a few examples so that you can relate the theory to a real problem and see how to approach questions 

3) I'll set you a few questions to try yourself 

If at any point you're struggling to grasp something then just interrupt me and we can take another look or try a different approach. Everyone works differently, so you tell me how you learn best and I'll adapt to that! 

If you'd like to have a chat about tutoring, then don't hesitate to get in touch. We can arrange a meet the tutor session as soon as possible!

Good luck, hope to see you soon!

Tom 

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Physics A Level £20 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr

Qualifications

QualificationLevelGrade
Mathematics A-LevelA*
PhysicsA-LevelA*
ChemistryA-LevelA
BiologyA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

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Questions Tom has answered

A simple circuit contains a battery rated at 12V, connected in series to a filament lamp with a resistance of 3 ohms. What current flows through the filament lamp?

V=IR, where V is voltage (volts), I is current (amps) and R is resistance (ohms). Since V and R are known, I needs to be found. Rearranging the equation gives: I=V/R. Inputting the values gives I=12/3. I=4A 

V=IR, where V is voltage (volts), I is current (amps) and R is resistance (ohms). Since V and R are known, I needs to be found. Rearranging the equation gives: I=V/R. Inputting the values gives I=12/3. I=4A 

11 months ago

223 views

Differentiate f(x) = 2xlnx.

Use the chain rule: f'(x) = v(du/dx) +u(dv/dx). Let u = 2x, du/dx = 2, v = lnx, dv/dx = 1/x Using this information: f'(x) = 2lnx + 2x/x This simplifies to f'(x) = 2lnx +2.

Use the chain rule: f'(x) = v(du/dx) +u(dv/dx).

Let u = 2x, du/dx = 2, v = lnx, dv/dx = 1/x

Using this information: f'(x) = 2lnx + 2x/x

This simplifies to f'(x) = 2lnx +2.

11 months ago

625 views

Find the solutions of the equation x^2 - 2x - 8 =0

First factorise the equation into 2 sets of brackets: You can do this by looking at the constant in the quadratic, 8. Try and find 2 numbers that multiply together to make 8 (such as 4 and 2), and that can be added or subtracted to make the coefficient of the middle term, 2. This results in: ...

First factorise the equation into 2 sets of brackets: You can do this by looking at the constant in the quadratic, 8. Try and find 2 numbers that multiply together to make 8 (such as 4 and 2), and that can be added or subtracted to make the coefficient of the middle term, 2. This results in: (x-4)(x+2)=0. To make the equation true, the left side must equal 0. Either bracket can equal 0. For the first let x=4 (as 4-4=0). For the second, x=-2. These are the answers, x=4 and x=-2 

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11 months ago

235 views
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