Hello! I'm Tom, I'm in my second year studying medical engineering at the University of Leeds. I've always loved sicence, being particularly drawn to physics and maths from a young age. I loved the methodical, logical approach to maths and its staggering relevance to everything from space travel to art (check out the golden ratio in the Mona Lisa). I've had experience tutoring in maths and chemistry previously, helping GCSE students to boost their grades in the run up to exams.
I know it can be really daunting thinking about that dreaded maths exam! Nevertheless, I'm here to assure you that there's nothing to fear, and that maths and physics can actually be enjoyable (shhh don't tell anyone).
During the tutorials, we will discuss any areas you're struggling with, then proceed to tackle topics like so:
1) I explain the general rules and principles surrounding the topic
2) I'll walk you through a few examples so that you can relate the theory to a real problem and see how to approach questions
3) I'll set you a few questions to try yourself
If at any point you're struggling to grasp something then just interrupt me and we can take another look or try a different approach. Everyone works differently, so you tell me how you learn best and I'll adapt to that!
If you'd like to have a chat about tutoring, then don't hesitate to get in touch. We can arrange a meet the tutor session as soon as possible!
Good luck, hope to see you soon!
|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
V=IR, where V is voltage (volts), I is current (amps) and R is resistance (ohms). Since V and R are known, I needs to be found. Rearranging the equation gives: I=V/R. Inputting the values gives I=12/3. I=4A
Use the chain rule: f'(x) = v(du/dx) +u(dv/dx).
Let u = 2x, du/dx = 2, v = lnx, dv/dx = 1/x
Using this information: f'(x) = 2lnx + 2x/x
This simplifies to f'(x) = 2lnx +2.
First factorise the equation into 2 sets of brackets: You can do this by looking at the constant in the quadratic, 8. Try and find 2 numbers that multiply together to make 8 (such as 4 and 2), and that can be added or subtracted to make the coefficient of the middle term, 2. This results in: (x-4)(x+2)=0. To make the equation true, the left side must equal 0. Either bracket can equal 0. For the first let x=4 (as 4-4=0). For the second, x=-2. These are the answers, x=4 and x=-2see more