Degree: Mathematics and Computer Science (Masters) - Bristol University
I am an undergraduate, Mathematics and Computer Science student at the University of Bristol. In 2014 I graduated from "Petru Rares" National College passing my Baccalaureate exam with 10/10 in Mathematics. I participated in numerous mathematics competitions and Olympiads; my best result was achieved in the 2014 "National Olympiad in Mathematics" where I obtained a Bronze Medal. In April 2013 I successfully attended a program called "Teacher for a day" on mathematics.
My expertise areas include topics such as Number Teory and Group Theory, Calculus & Analysis, Algebra, Complex Numbers, Linear Algebra (in particular vectors and matrices) and Combinatorics (specially elements of Graph Theory). As far as the tutorials are concerned I am happy to explain key concepts and useful results, solve problems of various levels of difficulty, check the solutions proposed by the student and compare them with model solutions, or anything else required.
Mathematics, apart from being extremely useful in our daily life, it is a very beautiful subject. Part of my task will be to help you see its beauty behind coplicated equations and, so called, "hard to remember" formulae. Once that is accomplished, problems will become exercises and exercises will become an easy and enjoyable task.
|Maths||A Level||£20 /hr|
|Romanian Language and Literature||Baccalaureate||9.60|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
First, we use 1 - sin(x)^2 = cos(x)^2 and get:
(LHS) (cos(x)^2 + 4 sin(x)^2)/(1-sin(x)^2)
= (cos(x)^2 + 4 sin(x)^2)/cos(x)^2
= 1 + 4 (sin(x)/cos(x))^2
= 1 + 4 tan(x)^2
Now we know that the left hand side is equal to 7.
Hence, 1 + 4 tan(x)^2 = 7 <=> tan(x)^2 = 3/2see more
First, notice that 1/(x^2) = x^(-2)
dy/dx = d/dx (x^(-2) + 4x)
The derivative of the sum is the sum of the derivatives
= d/dx (x^(-2)) + d/dx (4x)
The derivative of x^n is nx^(n-1), for every real number n, and a constant gets in front of the deivative
= -2 x^(-3) + 4 d/dx (x)
= -2/(x^3) + 4see more
If a quadratic equation is of the form : ax^2 +bx +c =0
and has roots x1 and x2, then the following statements are true:
x1+x2 = - b/a
x1*x2 = c/a
In our case: x1+x2 = - 8/2 = -4
and x1*x2 = 1/2
Now, x1^2 + x2^2 = (x1+x2)^2 -2*x1*x2
= (-4)^2 -2 * 1/2 = 16 - 1 = 15see more