Seair Q. A Level Maths tutor, 11 Plus Maths tutor, GCSE Maths tutor, ...

Seair Q.

Currently unavailable: for regular students

Degree: Civil Engineering (Bachelors) - Nottingham University

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About me

About me:

I am a first year Civil Engineering student, at the University of Nottingham. I am currently a Mentor at IntoUniversity and a STEM Ambassador at STEMNET, therefore I have a lot of experience with working young people, not to mention that I was previously a tutor too! I am someone, when given a certain task, complete it to the best of my ability and I aim to be the greatest at everything I do. I am very patient and an understanding person with a friendly presence.

From a young age till the first year of my A- Levels, I hated maths! This was mainly because I did not understand the content as well as coming from a disadvantaged background where I attended a school that was renowned for its badly-behaved students and below-average results. Conversely, by the end of A-Level I loved Mathematics.

Experience & Results:

- Went from achieving a C grade in GCSE Mathematics to achieving an A* in A-Level Mathematics.

-Tutored a group of 5-6 students with specific topics they had difficulty with, to prepare them for their Mathematic GCSE exam. 100% of the students taught were predicted Ds and C however, all achieved grade of A-B in their GCSE mathematics.

What can I give to you?

Results! If you are someone who hates Maths and believe that you are not good at it; no matter how bad you think yourself to be or how much you dislike it, I can help change your views as well as helping you to achieve any grade you want no matter how high it is. Like me who hated maths and was terrible at it, I completely turned it around and I can help you do that too!

What will happen during the sessions:

During the sessions, you will decide the topics we will cover and if you are unsure on what you need help with, I will help you by identifying your strengths and weaknesses. In mathematics, the key to succeed is to understand the concept of what you are learning with A LOT of practice, so before we do an exam question, I will make sure that you understand the topic I am teaching you thoroughly and once you are ready, we will do a lot of practice past papers as exam papers is a key resource in helping you achieve the best possible grade. I hope the sessions will be useful and fun! A lot can be learnt in 1 hour especially if it is made enjoyable!

Applying to an Engineering course and need help?

I can help! I had applied to various Russle group universities carrying AS-Level grades of BCE and received offers from all of them despite my poor grades. So I know how the whole UCAS process and how to make the process more simple whilst maximising what can be achieved from your application.

What next?

If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session', both accessible through this website.

I look forward to meeting you!

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Maths GCSE £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr
-Personal Statements- Mentoring £20 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

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Ratings and reviews

4.3from 6 customer reviews

Christianah (Student) October 20 2016

Good advice and explanations

Christianah (Student) September 22 2016

Very patient and gives great advice. Encourages confidence and builds up students independence. Great Tutorial.

Joshua (Student) April 17 2016

didnt attend

Gloria (Parent) September 29 2016

See all reviews

Questions Seair has answered

Integrate this funtion f'(x)=2x +4 with respect to x (C1 integration)

Solution to Answer: y= (2x^2)/2 + 4x + C Therefore: y= x^2 + 4x + C Steps on how to do C1 Integration y = a*x^n y = a*x^n is y = (a/n+1)*x^(n+1) Therefore, our final answer in this case is y = (a/n+1)*x^(n+1) + C.​ We add the integration constant as when we defrentiate a function f(x) and...

Solution to Answer:

y= (2x^2)/2 + 4x + C

Therefore:

y= x^2 + 4x + C

Steps on how to do C1 Integration

y = a*x^n

y = a*x^n is y = (a/n+1)*x^(n+1)

Therefore, our final answer in this case is y = (a/n+1)*x^(n+1) + C.​

We add the integration constant as when we defrentiate a function f(x) and have a constant in the equation, the constant goes. therfore when integrating we do the opposite of integration and hence add the integration constant C.

Differentiating the expression y=2x+2. 
The answer would be f'(x)= 2
Now when you integrate the expression f'(x) 
The answer would be y=2x 
Something is missing? 
As we don't know if there is a constant when we integrate and we also don't know its value we put the integration constant "C" to show the fact that there might be a constant. 
The correct answer for the integration of f'(x)=2 would be y=2x+c where c=2 in this case. 

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8 months ago

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