Currently unavailable: for regular students
Degree: Civil Engineering (Bachelors) - Nottingham University
|Maths||A Level||£20 /hr|
|Maths||13 Plus||£18 /hr|
|Maths||11 Plus||£18 /hr|
|-Personal Statements-||Mentoring||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Christianah (Student) October 20 2016
Christianah (Student) September 22 2016
Joshua (Student) April 17 2016
Gloria (Parent) September 29 2016
Solution to Answer:
y= (2x^2)/2 + 4x + C
y= x^2 + 4x + C
Steps on how to do C1 Integration
y = a*x^n
y = a*x^n is y = (a/n+1)*x^(n+1)
Therefore, our final answer in this case is y = (a/n+1)*x^(n+1) + C.
We add the integration constant as when we defrentiate a function f(x) and have a constant in the equation, the constant goes. therfore when integrating we do the opposite of integration and hence add the integration constant C.
Differentiating the expression y=2x+2.
The answer would be f'(x)= 2
Now when you integrate the expression f'(x)
The answer would be y=2x
Something is missing?
As we don't know if there is a constant when we integrate and we also don't know its value we put the integration constant "C" to show the fact that there might be a constant.
The correct answer for the integration of f'(x)=2 would be y=2x+c where c=2 in this case.