Caspar S. Uni Admissions Test .MAT. tutor, Mentoring -Personal Statem...

Caspar S.

Currently unavailable: for regular students

Degree: Mathematics, Operational Research, Statistics and Economics (Bachelors) - Warwick University

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About me

Me:

I study MORSE at Warwick University (unfortunately no, it's not morse code) and hope that my expertise in both teaching and learning maths (as well as a couple of other things) will translate into a great learning experience for you.

I've been tutoring for a couple of years and have also directed theatre productions, so I have a fair bit of experience with direction and teaching.

The lessons:

In these I'd hope that you provide me with an area/section (don't worry if it's the whole module!) you wish to cover, then we'd work through a foundation of understanding, and I will use as many analogies or sketches or what have you to try and best explain my thought process and help you understand the content. After a solid foundation is built, we'd move on to tackle exam and exam-style questions - and perhaps even slightly beyond that, to really affirm your knowledge.

I look forward to working with you!

Caspar.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £22 /hr
Maths A Level £22 /hr
English Literature GCSE £20 /hr
Maths GCSE £20 /hr
Physics GCSE £20 /hr
English 13 Plus £20 /hr
Maths 13 Plus £20 /hr
English 11 Plus £20 /hr
Maths 11 Plus £20 /hr
-Personal Statements- Mentoring £22 /hr
.MAT. Uni Admissions Test £25 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA*
English LiteratureA-LevelA*
PhysicsA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

General Availability

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Ratings and reviews

4.8from 15 customer reviews

Beverley (Parent) April 10 2016

Thanks Caspar - Leo got an A*!

Hussain (Student) April 11 2016

Very good knows his subjects

Safwan (Student) April 27 2016

Hussain (Student) April 29 2016

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Questions Caspar has answered

If y = (4x^2)ln(x) then find the second derivative of the function with respect to x when x = e^2 (taken from a C3 past paper)

The first thing to recognise is that this function is a product of two functions: namely, 4x^2 and ln(x), thus we must employ the product rule in order to find the solution. As you may recall, the product rule states that when you have a function f(x) = uv, the differential f'(x) = udv + vdu, ...

The first thing to recognise is that this function is a product of two functions: namely, 4x^2 and ln(x), thus we must employ the product rule in order to find the solution. As you may recall, the product rule states that when you have a function f(x) = uv, the differential f'(x) = udv + vdu, thus:

we differentiate once, finding that dy/dx = (4x^2)/x + 8xln(x) and simplify to get the expression 4x + 8xln(x)

then differentiate a second time, remembering to once again employ the product rule for the second term in the equation:

d^2y/dx^2 = 4 + (8 + 8ln(x))

now substitute the value of x = e^2 into the equation:

thus d^2y/dx^2 = 12 + 8ln(e^2)

now as we know that the natural logarithm "ln" is the inverse of the exponential function "e", this becomes:

d^2y/dx^2 = 12 + 8(2)

= 28.

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10 months ago

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