Imogen B. GCSE Maths tutor, 13 plus  Maths tutor

Imogen B.

Currently unavailable: until 03/06/2016

Degree: Mathematics (Bachelors) - Exeter University

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About me

I study maths at Exeter university. I have always had a passion for maths and applications of maths. Although I appreciate not all people share this passion, I believe that when taught on a individual basis everyone can enjoy maths.

While I was at school, I tutored maths to students between the ages of 13 and 16. I also coached a netball team for over 2 years of 12 year olds so I am used to adapting my teaching methods depending on age and ability. I am friendly and approachable and would ensure no two lessons were the same. 

I believe that the best way to learn maths is to discuss the topic to ensure thorough understanding and then to practice questions. I think getting to know the tutee is vital for me to be able to adapt my sessions to suit them.

Subjects offered

SubjectLevelMy prices
Maths GCSE £18 /hr
Maths 13 Plus £18 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
Further mathsA-LevelA*
EconomicsA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Questions Imogen has answered

How to solve the simultaneous equations 3x+2y=7 and 5x+y=14

Firstly we rearrange one of these equations so that we have y on one side of the equation on its own. Let's do this with the second equation. So from 5x+y=14, we can minus 5x from both sides to get: y=14-5x Then we can substitute this expression for y into our first equation that is 3x+2y=7 ...

Firstly we rearrange one of these equations so that we have y on one side of the equation on its own. Let's do this with the second equation.

So from 5x+y=14, we can minus 5x from both sides to get:

y=14-5x

Then we can substitute this expression for y into our first equation that is 3x+2y=7

So we have 3x+2(14-5x)=7

Then we expand the bracket: 

3x+(2)(14)+(2)(-5x)=7

By simplifying this equation we get:

3x+28-10x=7

And simplifying further gives:

7x=21

By dividing both sides by 7, we find that x=3.

We substitute this value for x into either of our original equations to find the value of y.

3(3)+2y=7

So 2y=7-9

And therefore y=-1.

Finally we can check our solutions by substituting x=3 and y=-1 into the other original equation.

Therefore the solutions are x=3 and y=-1.

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1 year ago

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