Currently unavailable: until 31/10/2016
Degree: Chemical Engineering (Masters) - Manchester University
I am a Chemical Engineering student at the University of Manchester. I am just going into my 2nd year at University. I enjoy teaching especially Mathematics. I show great passion while teaching and having taught students of all ages varying from Key Stage 2 all the way till A Level has given me great experience in the field of tutoring. I did Mathematics, Further Mathematics, Chemistry and Physics for A Levels and got 4A*s with an average of over 95 and therefore possess very good exam techniques which I am willing to share with my students to ensure they get the grades they would like to get.
I believe when teaching Mathematics, the key is practice. My first target would be to explain the chapter well to the student to make sure he/she understands it well. Following that it is all about practice. The quote 'Practice makes Perfect' applies very well in Mathematics. After practicing questions for a while, I make sure that the students do some past paper questions in the particular topic to try and apply the knowledge he/she has learnt in the topic to the actual exam type questions.
In addition to school work I can help students if they are applying to University for Engineering. Having spent two weeks at Cardiff Sixth Form College, which is the number one independent school in the UK, I helped their students with their personal statements, and prepared them for their admissions tests and interviews.
If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session'! (both accessible through this website). Remember to tell me your exam board and what you're struggling with.
I look forward to meeting you!
|Chemistry||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
The first method to differentiate this fuction is the basic chain rule method. differentiate 2x+1 and add this to the front of the function. This gives us 2e^(2x+1). the other method to differentiate this function is by using logs. if you log both sides base of e (ln), you get ln(y) = 2x+1 and then differentiating both sides with respect to x gives (1/y)*dy/dx= 2. This when rearranged gives dy/dx = 2y and we know that y = e^(2x+1). We end up with the same solution as before.see more
A catalyst provides an alternative pathway for a reaction to take place and therefore helping the reaction to take place at a lower activation energy. In an equilibrium process, a catalyst has no effect on the position of equilibrium. All it does is allow the reaction to reach equilibrium at a faster rate, but does not have any effect on the position of equilibrium. As always, the catalyst is not changed in the reaction.see more