Naheem A.

Naheem A.

Currently unavailable: for new students

Degree: BSc Mathematics (Bachelors) - Warwick University

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About me

An undergraduate mathematics student at the University of Warwick (ranked 3rd in the UK for mathematics).

I have several years of experience tutoring in the following subjects:

-Mathematics   -Further Mathematics   -Physics   -AEA   -STEP   -MAT and more.

- English  -Business Studies  -Science

I am taught a students of all ages and abilities and can help any individual get to where they want to be.

I achieved 10 A*s at GCSE and 3A*s and 1 A at A-level. This wide range of experience can help me offer expertise in many areas. I also won the Business Studies Prize at my sixth form and achieved 100% in many of my A-level exams including maths, business and physics. 


Past student examples: 

11 year old maths and english pupil: Tutored to help with entrance exams and general ability. Student was successful in getting into desired school.

18 year old maths A- Level: Helped a B grade student achieved an A* in A level mathematics.

17 year old Business Studies: Tutored a student who had achieved a D at AS level and they came out with a high B at A2. 

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £22 /hr
Maths A Level £22 /hr
Maths GCSE £20 /hr
Physics GCSE £20 /hr
Maths 13 Plus £20 /hr
Maths 11 Plus £20 /hr
.STEP. Uni Admissions Test £25 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA*
PhysicsA-LevelA*
Business StudiesA-LevelA
STEP 1Uni Admissions Test1 - 90/120
STEP 2 and STEP 3Uni Admissions Test2
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for new students

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Questions Naheem has answered

Where does the geometric series formula come from?

Rearranging the terms of the series into the usual "descending order" for polynomials, we get a series expansion of:   axn-1 +........ax + a A basic property of polynomials is that if you divide xn – 1 by x – 1, you'll get: xn–1 + xn–2 + ... + x3 + x2 + x + 1 That is:  a(xn–1 + xn–2 + ... ...

Rearranging the terms of the series into the usual "descending order" for polynomials, we get a series expansion of:  

axn-1 +........ax + a

A basic property of polynomials is that if you divide xn – 1 by x – 1, you'll get:

xn–1 + xn–2 + ... + x3 + x2 + x + 1

That is: 

a(xn–1 + xn–2 + ... + x3 + x2 + x + 1) = a(xn-1)/(x-1)

The above derivation can be extended to give the formula for infinite series, but requires tools from calculus. For now, just note that, for | r | < 1, a basic property of exponential functions is that rn must get closer and closer to zero as n gets larger. Very quickly, rn is as close to nothing as makes no difference, and, "at infinity", is ignored. This is, roughly-speaking, why the rn is missing in the infinite-sum formula.

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8 months ago

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