Contact Jamie
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About me

My name is Jamie and I am a 4th year Civil Engineering Student at Bristol University. I also spent my year abroad at McGill University in Canada. I have a real passion for Maths and Science, and love to share this passion with my students.

I am a relaxed and friendly character and have been tutoring for a long time. This will help us be efficient in the lessons and help you understand the material quickly.

With 4 A*s at A-Level, I am able to teach Maths, Further Maths, Physics and Chemistry, at either GCSE or A-Level. 

Outside of university I am a keen Windsurfer and am heading out to Greece this summer to teach in a resort out there. 

Tutoring methods

The lazy way of tutoring is to constantly feed the correct solutions to memorise, i will NOT take this approach. Together we will understand the question and the theory behind it. Then by prompting, hinting and guiding in the right direction, we will arrive at the solution.

Just like solving puzzles, Maths and Science can be fun if it's flowing and easy, and that will be the approach I take. 

I'm excited to meet you!

Thanks

Jamie Lowe

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £30 /hr
Maths A Level £30 /hr
Physics A Level £30 /hr
Chemistry GCSE £30 /hr
Maths GCSE £30 /hr
Physics GCSE £30 /hr
Science GCSE £30 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
Further MathsA-LevelA*
PhysicsA-LevelA*
ChemistryA-LevelA*
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

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Ratings and reviews

5from 27 customer reviews

Devell (Student) May 20 2016

Another amazing lesson Jamie clearly has a vast knowledge of maths and this is evident; his enthusiasm rubs off me and inspires me to do well!

Devell (Student) May 12 2016

another great lesson

Stuart (Parent) May 5 2016

Thanks Jamie

Devell (Student) May 5 2016

great lesson
See all reviews

Questions Jamie has answered

Expand and simplify (5x – 2y)(3x – 4y)

Expand and simplify (5x – 2y)(3x – 4y) In this question, we are asked to 'expand' out the brackets. What this means is we need each term in one set of brackets (5x and -2y) to be multiplied by each term in the other set of brackets (3x and -4y). So let's take this step-by-step. We're going t...

Expand and simplify (5x – 2y)(3x – 4y)

In this question, we are asked to 'expand' out the brackets. What this means is we need each term in one set of brackets (5x and -2y) to be multiplied by each term in the other set of brackets (3x and -4y).

So let's take this step-by-step.

We're going to use a simple technique which will help us in any future questions where we need to expand brackets. This is the FOIL technique:

F = first

O = outside

I  = inside

L = last

1) We start from of FOIL by multiplying together both of our first terms.

These are 5x and 3x because if we look at each bracket separately, these are the two individual terms that come first:

5x*3x = 15x^2

(5 times 3 = 15 and x times x = x^2)

2) Next we use of FOIL by multiplying together the terms on the outside of the brackets. 

These are 5x and -4y because when both brackets are side by side, we can see that these terms are on the outer part of the equation.

5x*-4y = -20xy

(5 times -4 = -20 and x times y = xy)

3) Then we use of FOIL by multiplying together the terms on the inside of the brackets. 

These are -2y and 3x because when both brackets are side by side, we can see that these terms are on the inner part of the equation.

-2y*3x = -6xy

(-2 times 3 = -6 and x times y = xy)

4) Finally we use L of FOIL by multiplying together the last terms of the brackets. 

These are -2y and -4y because if we look at each bracket separately, these are the two individual terms that come last:

-2y*-4y = 8y^2

(-2 times -4 = 8 and y times y = y^2)

5) Now let's look at what terms we're left with after each of those 4 steps using our FOIL technique:

15x^2 - 20xy - 6xy + 8y^2

Our last step is to 'simplify' our answer by collecting any like terms. These are terms which have the same algebraic ending when we ignore the number in front of them. 

So in this case, we have xy terms which we can collect: -20xy-6xy = -26xy.

6) Our final answer will be 15x^2 - 26xy + 8y^2.

REMEMBER:

Do check your signs when you look over your answers and your working. It's easy to make silly mistakes when you multiply a negative term with another negative term, for example (the answer will be positive).

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9 months ago

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