Henry N. 11 Plus Maths tutor, GCSE Maths tutor, IB Maths tutor, A Lev...

Henry N.

£18 - £20 /hr

Currently unavailable: for regular students

Studying: Physics (Masters) - Bristol University

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About me

About me

I am a second year physics student at the University of Bristol, with a keen interest in maths and phsyics. Over the past few years my life has been completely filled with maths and I hope that my fascination for the subject will come across in my tutorials! 

I am a very calm and relaxed person and advocate a laid-back teaching style, putting emphesis on keeping the tutorials both enjoyable and productive. This will involve guiding the student through any questions or problems they might have with the subject and hopefully providing them with the tools needed to tackle any problems in the future!

About me

I am a second year physics student at the University of Bristol, with a keen interest in maths and phsyics. Over the past few years my life has been completely filled with maths and I hope that my fascination for the subject will come across in my tutorials! 

I am a very calm and relaxed person and advocate a laid-back teaching style, putting emphesis on keeping the tutorials both enjoyable and productive. This will involve guiding the student through any questions or problems they might have with the subject and hopefully providing them with the tools needed to tackle any problems in the future!

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A
PhysicsA-level (A2)A
Further mathsA-level (A2)B

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr
MathsIB£20 /hr
Maths13 Plus £18 /hr
Maths11 Plus£18 /hr

Questions Henry has answered

Solve the quadratic 2x^2+7x+6 by completing the square

All quadratic equations take the general form:

ax2+bx+c=0

The first step used to comlete the square is to divide the whole equation by the a term, in our case 2:

1)        x2+(7/2)x+3=0

We then move our c term to the right hand side of the equation by subtracting from both sides:

2)        x2+(7/2)x=_3

Let us, for a moment, just examine the left hand side of this equation. We can see that:

3)        (x+7/4)2=x2+(7/2)x+(7/4)2

Therefore:

4)         x2+(7/2)x=(x+7/4)2-(7/4)2

Inserting equation 4 into equation 2 gives:

5)        (x+7/4)2-(7/4)2=_3

We can re-arrange to get:

6)        (x+7/4)2=_3+(7/4)2

Simplifying the right hand side gives:

7)        (x+7/4)2=1/16

Taking the square root of both sides gives(baring in mind that taking the square root of a number gives us a positive and a negative number):

8)        x+7/4=+1/4

Finally subtracting 7/4 leaves us with our answer:

9)        x=_3/2 or x=_2

All quadratic equations take the general form:

ax2+bx+c=0

The first step used to comlete the square is to divide the whole equation by the a term, in our case 2:

1)        x2+(7/2)x+3=0

We then move our c term to the right hand side of the equation by subtracting from both sides:

2)        x2+(7/2)x=_3

Let us, for a moment, just examine the left hand side of this equation. We can see that:

3)        (x+7/4)2=x2+(7/2)x+(7/4)2

Therefore:

4)         x2+(7/2)x=(x+7/4)2-(7/4)2

Inserting equation 4 into equation 2 gives:

5)        (x+7/4)2-(7/4)2=_3

We can re-arrange to get:

6)        (x+7/4)2=_3+(7/4)2

Simplifying the right hand side gives:

7)        (x+7/4)2=1/16

Taking the square root of both sides gives(baring in mind that taking the square root of a number gives us a positive and a negative number):

8)        x+7/4=+1/4

Finally subtracting 7/4 leaves us with our answer:

9)        x=_3/2 or x=_2

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2 years ago

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