Callum H. A Level Maths tutor, GCSE Maths tutor, A Level Economics tu...

Callum H.

£20 - £22 /hr

Currently unavailable:

Studying: Economics (Bachelors) - Bristol University

5.0
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1 review| 14 completed tutorials

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About me

About Me:

I am a second year Economics student at the University of Bristol and a keen mathematics enthusiast! I have had the pleasure of tutoring for three years now and have had an excellent record of helping many students get the highest grade achievable!

The Sessions:

I want you to get exactly what you want out of the sessions. I can help with anything from revisiting content you have previously gone over in class or help going through past exam questions. Just let me know what you want to do and I'll be happy to help.

What Next?

If you have any questions, please book a 'Meet the Tutor Session'! and remember to tell me your exam board, what modules you are studying (if you are an A-Level student) and what you're struggling with.

I look forward to working with you!

About Me:

I am a second year Economics student at the University of Bristol and a keen mathematics enthusiast! I have had the pleasure of tutoring for three years now and have had an excellent record of helping many students get the highest grade achievable!

The Sessions:

I want you to get exactly what you want out of the sessions. I can help with anything from revisiting content you have previously gone over in class or help going through past exam questions. Just let me know what you want to do and I'll be happy to help.

What Next?

If you have any questions, please book a 'Meet the Tutor Session'! and remember to tell me your exam board, what modules you are studying (if you are an A-Level student) and what you're struggling with.

I look forward to working with you!

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Ratings & Reviews

5from 1 customer review
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Layla (Parent)

May 10 2016

Callum was very nice and helped me really well. He helped me understand things that I never could've taught myself. He has a lot of patience and didn't mind repeating the same things a million times till I got it. Definitey learnt a lot from Callum and definitely recommend him!

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Qualifications

SubjectQualificationGrade
Further MathsA-level (A2)A*
MathsA-level (A2)A*
PhysicsA-level (A2)A*
GeographyA-level (A2)A*
Extended Project QualificationA-level (A2)A*

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
EconomicsA Level£22 /hr
MathsA Level£22 /hr
EconomicsGCSE£20 /hr
MathsGCSE£20 /hr

Questions Callum has answered

A curve has equation y = 4x + 1/(x^2) find dy/dx.

As in every case dy/dx can be found by differentiating each term individually with respect to x.

Let's first tackle the 4x term.

As always the derivative can be found by multiplying the term by the power of x and reducing the power of x by 1. i.e. axb -> abxb-1

In this case b is simply equal to 1 because x=x1. Therefore the derivative of 4x with respect to x is given by 1*4x= 4*1 = 4.

Next let's tackle the 1/x2 term.

In order to use the same method as previously we must first write 1/xas a power of x i.e. in the familiar form axb.

From the laws of indices: recall that x-b=1/xb. In this example b is simply equal to 2 so 1/x2=x-2.

Now that we have written the term in the form axb we can apply the same method as previously i.e.   x-2-> -2x-3.

Finally collecting both the terms we have arrived at the result that dy/dx is -2x-3+4.

As in every case dy/dx can be found by differentiating each term individually with respect to x.

Let's first tackle the 4x term.

As always the derivative can be found by multiplying the term by the power of x and reducing the power of x by 1. i.e. axb -> abxb-1

In this case b is simply equal to 1 because x=x1. Therefore the derivative of 4x with respect to x is given by 1*4x= 4*1 = 4.

Next let's tackle the 1/x2 term.

In order to use the same method as previously we must first write 1/xas a power of x i.e. in the familiar form axb.

From the laws of indices: recall that x-b=1/xb. In this example b is simply equal to 2 so 1/x2=x-2.

Now that we have written the term in the form axb we can apply the same method as previously i.e.   x-2-> -2x-3.

Finally collecting both the terms we have arrived at the result that dy/dx is -2x-3+4.

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2 years ago

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