Currently unavailable: until 31/05/2016
Degree: Actuarial Sciences (Masters) - Manchester University
I am a mathematics graduate, currently studying towards an MSc in Actuarial Science at the University of Manchester. I have always enjoyed solving mathematical problems and hope that my tutorials will help you grasp the mathematical concepts I have grown to love.
I am very patient and friendly. I have previously worked as a statistics tutor for a PhD medical student and am currently working as a weekly mathematics tutor for a GCSE student, so I have a lot of experience in teaching people of different ages and backgrounds.
During the sessions, you will guide me on what we cover. In maths, understanding the concepts is key, so before we do exam questions, we will focus on this.
I will use as many different ways as possible to explain the concepts and use plenty of examples to ensure you understand them. We will then work through relevant mathsy problems, until I am sure you are 100% confident with the concept.
I hope the sessions will be fun! A lot can be achieved in 55mins especially if it is made enjoyable - maths is amazing and hopefully, if you didn’t think that before, you will by the end of the session!
If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session'! (both accessible through this website). Remember to tell me your exam board and what you're struggling with.
I look forward to meeting you!
|Maths||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
We recognise that this is in the form of a function within a function, i.e u= 3x - 2 is within the u^4 function, therefore here we will use the chan rule to differentiate the equation.
The chain rule states that dy/dx = dy/du * du/dx.
Here let u = 3x -2, then du/dx = 3. Similarly, y=u^4 so dy/du = 4u^3. Therefore dy/dx = 3 * 4u^3 = 12u^3.
Finally, we substitute u = 3x - 2 into the equation. This therefore gives us, dy/dx = 12(3x - 2)^3.see more
Ok so we need to get 'y' by itself on the left hand side of equal sign. We will first try to remove the denominator by multiplying 'x' by (3+4y). This gives (3+4y)x = 1 - 2y.
We will then expand the brackets so we can get a sum of the single terms i.e this gives 3x + 4yx = 1 - 2y.
We will now gather all terms with 'y' on the left hand side of the equal sign. This gives 4yx + 2y = 1 - 3x.
Now we factorise to get a single 'y' term, this gives (4x +2)y= 1 - 3x.
We finally try to get 'y' on its own by divinding both sides of the equal sign by (4x +2). This therefore gives us y = (1-3x)/ (4x +2) which is our final answer!see more