About me
About Me: I'm Chloe and I'm a 2nd year maths student at Bristol university. I've always enjoyed working with numbers and I hope that I can encourage others to love working with them too! I've tutored both of my siblings through their A level and GCSE maths. I'm very patient and understand that some concepts of maths can be very difficult to grasp. What I can do for you: The sessions will revolve around subjects you are struggling with. I can help you work through examples and show you the methods needed to solve problems, as well as helping you understand them. I can also help with exam questions if you let me know which exam board you are taking.
About Me: I'm Chloe and I'm a 2nd year maths student at Bristol university. I've always enjoyed working with numbers and I hope that I can encourage others to love working with them too! I've tutored both of my siblings through their A level and GCSE maths. I'm very patient and understand that some concepts of maths can be very difficult to grasp. What I can do for you: The sessions will revolve around subjects you are struggling with. I can help you work through examples and show you the methods needed to solve problems, as well as helping you understand them. I can also help with exam questions if you let me know which exam board you are taking.
No DBS Check
Ratings & Reviews
Dor (Parent from London)
March 12 2017
She did well
Chandra (Parent from Milton Keynes)
February 23 2017
Very good
Areeba (Student)
February 15 2017
She explained everything in detail and went through all the practice questions with me, giving me questions to do at the end to make sure i understand. She also answered all of my questions regarding the topic.
Emma (Parent from Hove)
February 7 2017
thank uuuuuuu
Qualifications
General Availability
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Subjects offered
Questions Chloe has answered
How do you find the integral of sin^2(x) dx?
Sin^2(x) cannot be integrated in its current form so you must use trigonometric identities to change sin^2(x) into something else.
Use the formula for cox(2x): cos(2x)=cos(x+x)=cos^2(x)-sin^2(x)
Now use that cos^2(x)=(1-sin^2(x))
So cos(2x)=1-2sin^2(x)
Rearrange the equation to find that sin^2(x)=1/2-1/2(cos(2x))
Now you can integrate to get that the integral of sin^2(x)=1/2x-1/4sin(2x)
Sin^2(x) cannot be integrated in its current form so you must use trigonometric identities to change sin^2(x) into something else.
Use the formula for cox(2x): cos(2x)=cos(x+x)=cos^2(x)-sin^2(x)
Now use that cos^2(x)=(1-sin^2(x))
So cos(2x)=1-2sin^2(x)
Rearrange the equation to find that sin^2(x)=1/2-1/2(cos(2x))
Now you can integrate to get that the integral of sin^2(x)=1/2x-1/4sin(2x)
